powershell to get one specific colume value from one row

Question

if the output is like this

java 14.59%

i want to get the the second colume (14.59% ) and save in one parameter.
how to do that ?

Answer 1

This works (assuming the column separator's a space):

$string = "java 14.59%"
($string -split " ")[1]

If there are multiple spaces (or tabs or other 'whitespace' characters) separating the columns, then this will work:

$string -replace  "^.+?\s+(.+)$",'$1'

Or even this (if it's always spaces as separators):

$string.split(" ",[System.StringSplitOptions]::RemoveEmptyEntries)[1]

Answer 2

 $string -replace  "^.+?\s+(.+)$",'$1'   is working for me  , thanks you very much.

now , i can get 14.59%. another question is how to remove % form 14.59% ？
what i want is 14.59 .

Answer 3

Hi @Yonglong YL44 Wang ,

this should help:

"14.59%" -Replace "%",""  
  
# or this way:  
  
$b = "14.59%"  
$b.Replace("%","")  

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(If the reply was helpful please don't forget to upvote and/or accept as answer, thank you)

Regards
Andreas Baumgarten