Font.Equals(Object) Method

Reference

Definition

Namespace:: System.Drawing

Assembly:: System.Drawing.Common.dll

Assembly:: System.Drawing.dll

Package:: System.Drawing.Common v10.0.0-preview.1.25080.3

Source:: Font.cs

Source:: Font.cs

Source:: Font.cs

Source:: Font.cs

Source:: Font.cs

Source:: Font.cs

Important

Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.

Indicates whether the specified object is a Font and has the same FontFamily, GdiVerticalFont, GdiCharSet, Style, Size, and Unit property values as this Font.

public:
 override bool Equals(System::Object ^ obj);

public override bool Equals(object? obj);

public override bool Equals(object obj);

override this.Equals : obj -> bool

Public Overrides Function Equals (obj As Object) As Boolean

Parameters

obj: Object

The object to test.

Returns

Boolean

true if the obj parameter is a Font and has the same FontFamily, GdiVerticalFont, GdiCharSet, Style, Size, and Unit property values as this Font; otherwise, false.

Examples

The following code example is designed for use with Windows Forms, and it requires PaintEventArgs e, which is a parameter of the Paint event handler. The code creates two Font objects and then tests whether they are equivalent.

public:
   void Equals_Example( PaintEventArgs^ /*e*/ )
   {
      // Create a Font object.
      System::Drawing::Font^ firstFont = gcnew System::Drawing::Font( "Arial",16 );

      // Create a second Font object.
      System::Drawing::Font^ secondFont = gcnew System::Drawing::Font( gcnew FontFamily( "Arial" ),16 );

      // Test to see if firstFont is identical to secondFont.
      bool fontTest = firstFont->Equals( secondFont );

      // Display a message box with the result of the test.
      MessageBox::Show( fontTest.ToString() );
   }

public void Equals_Example(PaintEventArgs e)
{
    // Create a Font object.
    Font firstFont = new Font("Arial", 16);
             
    // Create a second Font object.
    Font secondFont = new Font(new FontFamily("Arial"), 16);
             
    // Test to see if firstFont is identical to secondFont.
    bool fontTest = firstFont.Equals(secondFont);
             
    // Display a message box with the result of the test.
    MessageBox.Show(fontTest.ToString());
}

Public Sub Equals_Example(ByVal e As PaintEventArgs)

    ' Create a Font object.
    Dim firstFont As New Font("Arial", 16)

    ' Create a second Font object.
    Dim secondFont As New Font(New FontFamily("Arial"), 16)

    ' Test to see if firstFont is identical to secondFont.
    Dim fontTest As Boolean = firstFont.Equals(secondFont)

    ' Display a message box with the result of the test.
    MessageBox.Show(fontTest.ToString())
End Sub

Applies to

Продукт	Версии
.NET	8 (package-provided), 9 (package-provided), 10 (package-provided)
.NET Framework	1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard	2.0 (package-provided)
Windows Desktop	3.0, 3.1, 5, 6, 7, 8, 9, 10

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