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ErrorEventArgs.GetException Method

Definition

Gets the Exception that represents the error that occurred.

C#
public virtual Exception GetException();

Returns

An Exception that represents the error that occurred.

Examples

The following example creates a new instance of ErrorEventArgs and initializes it with an Exception. Then the example calls GetException to retrieve the Exception and display the error message. There is no form associated with this code.

C#

public static void Main(string[] args) {
   //Creates an exception with an error message.
   Exception myException= new Exception("This is an exception test");

   //Creates an ErrorEventArgs with the exception.
   ErrorEventArgs myErrorEventArgs = new ErrorEventArgs(myException);

   //Extracts the exception from the ErrorEventArgs and display it.
   Exception myReturnedException = myErrorEventArgs.GetException();
   MessageBox.Show("The returned exception is: " + myReturnedException.Message);
}

Applies to

Продукт Версии
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9, 10
.NET Framework 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 2.0, 2.1