FontDialog.ShowColor Property

Definition

Gets or sets a value indicating whether the dialog box displays the color choice.

C#
public bool ShowColor { get; set; }

Property Value

true if the dialog box displays the color choice; otherwise, false. The default value is false.

Examples

The following code example uses ShowDialog to display a FontDialog. This code requires that a Form has already been created with a TextBox and button placed on it. It also requires that the fontDialog1 has been created. The Font contains the size information but not the color information.

C#
private void button1_Click(object sender, System.EventArgs e)
 {
    fontDialog1.ShowColor = true;

    fontDialog1.Font = textBox1.Font;
    fontDialog1.Color = textBox1.ForeColor;

    if(fontDialog1.ShowDialog() != DialogResult.Cancel )
    {
       textBox1.Font = fontDialog1.Font ;
       textBox1.ForeColor = fontDialog1.Color;
    }
 }

Applies to

Product Versions
.NET Framework 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
Windows Desktop 3.0, 3.1, 5, 6, 7, 8, 9, 10

See also