Hi Ryan
Thanks for the answer.
I just checked my deployment file
[
{
"log_time": "2020-09-29T19:12:03.0026083Z",
"id": "0976dcd7-51a5-4254-8a90-6417ab85f9f6",
"message": "Updating submodules.",
"type": 0,
"details_url": null
},
{
"log_time": "2020-09-29T19:12:03.0287668Z",
"id": "516c780d-5393-41c1-a719-cb9956caa83c",
"message": "Preparing deployment for commit id 'b20cee4df3'.",
"type": 0,
"details_url": null
},
{
"log_time": "2020-09-29T19:12:03.0952114Z",
"id": "3715723c-be43-429b-9879-29664dfe6312",
"message": "Repository path is /tmp/zipdeploy/extracted",
"type": 0,
"details_url": null
},
{
"log_time": "2020-09-29T19:12:03.1194585Z",
"id": "9d0ae73e-a1be-4f79-ad03-bd6f9a5c8674",
"message": "Running oryx build...",
"type": 2,
"details_url": "https://XXXX.scm.dev001./api/deployments/b20cee4df3e64a7d90967c1d41c1ddf1/log/9d0ae73e-a1be-4f79-ad03-bd6f9a5c8674"
}
]
when i click on the Log, it would be like below
found 4 vulnerabilities (3 low, 1 high)
rsync: recv_generator: failed to stat "/home/site/wwwroot/controllers\xxx.js": Invalid argument (22)
Can you help me with the above
i checked the zip file and it seems to have all the contents in it
Hi Ryan,
I was on Leave. Sorry for the Late Reply.
when i zip thru powershell command like below
Compress-Archive -Path dsdsf/* -DestinationPath common-suj1.zip
it zips the file.
Then i Post the CURL like below
curl -k -X POST --data-binary @"Common-14.zip" https://$XXX:XXXX@.scm.dev001..xx.com/api/zipdeploy -v
i see the logs like below
it ignored the index.js file package.json etc
when i unzipped and saw the file They are all present. Please find the attached screenshot.
when i manually did the Send to Zip and used the CURL it works. i could see the Logs like below