show label data based on gridview data

RAVI 1,056 Reputation points
2024-04-04T05:37:32.4866667+00:00

Hello

I have girdivew1 in that i have this data forexample

User's image

And i have one dropdownlist and one label

if i select from dropdownlist MANGO it has to in label as 10

if i select from dropdownlist APPLE it has to in label as 4

how to do so

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  1. Lan Huang-MSFT 29,336 Reputation points Microsoft Vendor
    2024-04-04T07:32:44.8933333+00:00

    Hi @RAVI,

    Is your girdivew data obtained from the database? If so, you can refer to the code below.

    <html xmlns="http://www.w3.org/1999/xhtml">
    <head runat="server">
        <title></title>
        <script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.7.1/jquery.min.js"></script>
        <script>
            $(function () {
                $("#DropDownList1").change(function () {
                    document.getElementById('Label1').innerHTML = this.value;
                })
            })
        </script>
    </head>
    <body>
        <form id="form1" runat="server">
            <div>
                <asp:DropDownList ID="DropDownList1" runat="server"></asp:DropDownList>
                <asp:Label ID="Label1" runat="server"></asp:Label>
                <asp:GridView ID="GridView1" runat="server"></asp:GridView>
            </div>
        </form>
    </body>
    </html>
    
    protected void Page_Load(object sender, EventArgs e)
    {
        if (!this.IsPostBack)
        {
            string constr = ConfigurationManager.ConnectionStrings["ConString"].ConnectionString;
            using (SqlConnection con = new SqlConnection(constr))
            {
                using (SqlCommand cmd = new SqlCommand("SELECT Field1,  Field2, Field3 FROM Table_1"))
                {
                    using (SqlDataAdapter sda = new SqlDataAdapter())
                    {
                        cmd.Connection = con;
                        sda.SelectCommand = cmd;
                        using (DataTable dt = new DataTable())
                        {
                            sda.Fill(dt);
                            GridView1.DataSource = dt;
                            GridView1.DataBind();
                            DropDownList1.DataSource = dt;
                            DropDownList1.DataBind();
                            DropDownList1.DataValueField = "Field2";
                            DropDownList1.DataTextField = "Field1";
                            DropDownList1.DataBind();
                            DropDownList1.Items.Insert(0, "Select");
                        }
                    }
                }
            }
        }
    }
    

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    Best regards,
    Lan Huang


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