Programmatically assign a UserControl to a DataTemplate

Question

I'm trying to create a datagrid only by using c# without xaml because at compile time i don't know anything about the data that i will receive.

So i need to use the only DataGridTemplateColumn but to archieve this i need to assign a value to the dataTemplate property.

Somewhere i read about the possibility to use a generic usercontrol as dataTemplate but without success.

So how can i archieve this without using xaml defined datatemplate?

Answer 1

Hi @Luca Iovene , Welcome to Microsoft Q&A,

Dynamically create the DataTemplate of DataGridTemplateColumn in C#, without relying on XAML, and use FrameworkElementFactory to build the template content. You can dynamically generate a DataTemplate for DataGridTemplateColumn and define different UI elements for each cell.

using System.Collections.Generic;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;

namespace _xxx
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();
            DynamicDataGrid dynamicDataGrid = new DynamicDataGrid();
            DataGrid dataGrid = dynamicDataGrid.CreateDataGrid();
            MainGrid.Children.Add(dataGrid);
            List<MyData> data = new List<MyData>
            {
                new MyData { Value = "Item 1" },
                new MyData { Value = "Item 2" },
                new MyData { Value = "Item 3" }
            };
            dataGrid.ItemsSource = data;
        }
        public class MyData
        {
            public string Value { get; set; }
        }

///Programmatically assign a UserControl to a DataTemplate
        public class DynamicDataGrid
        {
            public DataGrid CreateDataGrid()
            {
                DataGrid dataGrid = new DataGrid();
                DataGridTemplateColumn templateColumn = new DataGridTemplateColumn();
                templateColumn.Header = "Dynamic Column";
                DataTemplate cellTemplate = new DataTemplate();
                FrameworkElementFactory textBlockFactory = new FrameworkElementFactory(typeof(TextBlock));
                Binding binding = new Binding("Value");
                textBlockFactory.SetBinding(TextBlock.TextProperty, binding);
                cellTemplate.VisualTree = textBlockFactory;
                templateColumn.CellTemplate = cellTemplate;
                dataGrid.Columns.Add(templateColumn);
                return dataGrid;
            }
        }
    }
}

Best Regards,

Jiale

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