Code to split x³

Question

I got help from the for to split exponents , but the below code won't split x³

I want output as x and 3

using System;
using System.Text;
using System.Text.RegularExpressions;
string input = "2³";
Regex regex = new Regex(@"(\d+)([\xB2\xB3\xB9\u2070\u2074-\u2079]+)");
Match match = regex.Match(input);
if (match.Success)
{
    int baseNum = int.Parse(match.Groups[1].Value);
    System.Console.WriteLine(baseNum);
   
   int exponent = int.Parse( match.Groups[2].Value.Normalize( NormalizationForm.FormKC ) );
    System.Console.WriteLine(exponent);
    
    
}
else
{
    Console.WriteLine("No match found.");
}
 

Answer 1

Hi @Kalyan A , Welcome to Microsoft Q&A,

Since QA cannot mark his own questions, I will repost your answer to close this case. So the solution to the issue is as follow:

using System;
using System.IO;
using System.Text;
using System.Text.RegularExpressions;
class Program
{
    static void Main()
    {
        string input = "2y²x³";
        int len1 =   input.Length;;
      //  Console.WriteLine(len1);
        string invalidPattern = @"[a-zA-Z]\d";
        bool containsInvalid = Regex.IsMatch(input, invalidPattern);
        string patternx = @"^[a-zA-Z0-9]+$";
        Regex regex1 = new Regex(patternx);
       containsInvalid = Regex.IsMatch(input, patternx);
         if (ContainsLettersAndDigitsOnly(input))
        { containsInvalid =false; }
         else
        { containsInvalid = true; }
        if (containsInvalid)
        {
            Console.WriteLine("Invalid monomials found (letters followed by digits):");
        }
        else
        {
            // Regex pattern to split by superscripts, letters, and digits
            string pattern = @"([\xB2\xB3\xB9\u2070\u2074-\u2079]+|[a-zA-Z]|\d)";
            // Use Regex.Split to split the input string based on the given pattern
            string[] result = Regex.Split(input, pattern);
            // Output the results, filtering out empty entries
            foreach (string s in result)
            {
                if (!string.IsNullOrEmpty(s))
                {
                    Console.WriteLine(s.Normalize(NormalizationForm.FormKC));
                }
            }
        }
        static bool ContainsLettersAndDigitsOnly(string input)
        {
            // Regular expression to check if the string contains both letters and digits, and no other characters
            return Regex.IsMatch(input, @"^[A-Za-z\d\u00B2\u00B3\u2070-\u207F]+$");
        }
    }
}

Best Regards,

Jiale

---

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Answer 2

using System;
using System.IO;
using System.Text;
using System.Text.RegularExpressions;
class Program
{
    static void Main()
    {
        string input = "2y²x³";
        int len1 =   input.Length;;
      //  Console.WriteLine(len1);
        string invalidPattern = @"[a-zA-Z]\d";
        bool containsInvalid = Regex.IsMatch(input, invalidPattern);
        string patternx = @"^[a-zA-Z0-9]+$";
        Regex regex1 = new Regex(patternx);
       containsInvalid = Regex.IsMatch(input, patternx);
         if (ContainsLettersAndDigitsOnly(input))
        { containsInvalid =false; }
         else
        { containsInvalid = true; }
        if (containsInvalid)
        {
            Console.WriteLine("Invalid monomials found (letters followed by digits):");
        }
        else
        {
            // Regex pattern to split by superscripts, letters, and digits
            string pattern = @"([\xB2\xB3\xB9\u2070\u2074-\u2079]+|[a-zA-Z]|\d)";
            // Use Regex.Split to split the input string based on the given pattern
            string[] result = Regex.Split(input, pattern);
            // Output the results, filtering out empty entries
            foreach (string s in result)
            {
                if (!string.IsNullOrEmpty(s))
                {
                    Console.WriteLine(s.Normalize(NormalizationForm.FormKC));
                }
            }
        }
        static bool ContainsLettersAndDigitsOnly(string input)
        {
            // Regular expression to check if the string contains both letters and digits, and no other characters
            return Regex.IsMatch(input, @"^[A-Za-z\d\u00B2\u00B3\u2070-\u207F]+$");
        }
    }
}