How to get PartId from table #trades where it have parts that have only map To and not have map From depend on table #map ?

Question

I work on SQL server 2012 I have issue I can't get Part Id that have only map

To and not have map From

depend on table #map ?

every part id must be found on table trades two times

first row for same part for map from code type from and code value from
second row for same part for map to code type to and code value to

meaning every part must exist two time

but if it exist as one time for part as map To code type and code value

and not have map From code type and code value

then this

what I need to display because it not have map From

as example parts 1410,1445,1445,1485,1348,1850 have map To only so it must display

part 1348 no need to display or show because it have map from and map to

so How to write query on SQL server 2012 display parts from table trades that have map To only and not have map From depend on table #map ?

create table #trades
(
PartId int,
CodeTypeId int,
Code int,
PartLevel int
)
insert into #trades(PartId,CodeTypeId,Code,PartLevel)
values
(1348,9090,13456,0),
(1348,7070,13000,0),
(1387,9090,13456,0),
(1387,7070,13000,0),
(1390,9090,13456,0),
(1390,7070,13000,0),
(1800,9095,13570,0),
(1800,7075,14000,0),
(1850,9095,13570,0),
(1850,7075,14000,0),
(1400,7070,13000,0),
(1410,7070,13000,0),
(1445,7075,14000,0),
(1485,7075,14000,0),
(1348,7075,14000,0),
(1850,7070,13000,0)

 create table #map
 (
 MapId int,
 CodeTypeFrom int,
 CodeTypeTo int,
 CodeValueFrom int,
 CodeValueTo int
 )
 insert into #map(MapId,CodeTypeFrom,CodeTypeTo,CodeValueFrom,CodeValueTo)
 values
 (3030,9090,7070,13456,13000),
 (3035,9095,7075,13570,14000)

expected result

TradeCodesId    PartId  CodeTypeId  Code    PartLevel
11  1400    7070    13000   0
12  1410    7070    13000   0
13  1445    7075    14000   0
14  1485    7075    14000   0
15  1348    7075    14000   0
16  1850    7070    13000   0

Answer 1

Hi @ahmed salah ，

For different CodeTypeTo with the same PartId, you need to provide a fixed order to return the result you expect.

For different CodeTypeTo with the same PartId, you need to provide a fixed order to return the result you expect. The data you provide is actually in no order. The first row and the second row you mentioned are just data returned by sql server randomly. Therefore, currently only the following results can be achieved, that is, for PartIds with two CodeTypeTos, only one CodeTypeTo can be returned randomly:

    ;with except_all as  
     (select row_number()   
             over(partition by PartId  
       order by(select 0)) as rn, PartId  
       from (select PartId from #trades  
     where CodeTypeId in (select CodeTypeTo from #map)) t  
     except  
     select row_number()   
             over(partition by PartId  
       order by(select 0)) as rn, PartId  
       from (select PartId from #trades  
    where CodeTypeId in (select CodeTypeFrom from #map)) t)  
    ,cte2 as  
    (select e.PartId,t.CodeTypeId,t.code,t.PartLevel,row_number() over(partition by t.PartId order by t.PartId) rr   
    from  except_all e  
    join #trades t on e.PartId=t.PartId  
    where t.CodeTypeId not in (select CodeTypeFrom from #map))  
      
    select PartId,CodeTypeId,code,PartLevel from cte2   
    where rr<2  

Output:

Regards
Echo

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