Value from DataGridViewRow Getting Error in C#

NazHim 201

hello I am using C# I want to get Column Value from DataGridViewRow using Column Name foreach (DataGridViewRow row in studentsDataGridView.Rows) { MarksOne += Convert.ToDecimal(row.Cells["Stu_MarOne"].Value.ToString()); MarksTwo += Convert.ToDecimal(row.Cells["Stu_MarTwo"].Value.ToString()); MarksThree += Convert.ToDecimal(row.Cells["Stu_MarThre"].Value.ToString()); } Getting Error why? Some Pages it's working perfectly but getting error in this page..? anybody can help me..! Image also attached![77791-screenshot-2021-03-15-155911.png][1] [1]: /api/attachments/77791-screenshot-2021-03-15-155911.png?platform=QnA

Accepted answer

Karen Payne MVP 35,466 Reputation points

2021-03-15T11:19:02.367+00:00
Looks like you have used the wrong column name, run the following before the failing code to get column names to verify the column name.

foreach (DataGridViewColumn dataGridViewColumn in studentsDataGridView.Columns) { Debug.WriteLine(dataGridViewColumn.Name); }
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NazHim 201 Reputation points

2021-03-15T11:27:50.57+00:00

thanks for your fast response
Stu_MarOne
it's Table Field's Name
i want to get Stu_MarOne's Row Value from DataGridViewRow
Regards

Karen Payne MVP 35,466 Reputation points

2021-03-15T11:48:57.83+00:00

Stu_MarOne may be in the table but obviously it's not the column name in the DataGridView which is why I asked you to run the foreach. This is because you may have a column name in the database table called Stu_MarOne but a column name in the DataGridView different e.g.

Here is another check you can run, rather than look at a column names check one column name. You need to run my first check or this check to validate the column name exists.

Debug.WriteLine(studentsDataGridView.Columns.Contains("Stu_MarOne") ? "Column Stu_MarOne exists" : "Column Stu_MarOne does not exists");

NazHim 201 Reputation points

2021-03-15T13:59:16.963+00:00

thanks
karenpayneoregon

Karen Payne MVP 35,466 Reputation points

2021-03-15T14:14:48.36+00:00

Your very welcome.
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