SqlError.Source Property

Definition

Namespace:

System.Data.SqlClient

Assembly:

System.Data.SqlClient.dll

Package:

System.Data.SqlClient v4.8.6

Gets the name of the provider that generated the error.

public:
 property System::String ^ Source { System::String ^ get(); };

public string Source { get; }

member this.Source : string

Public ReadOnly Property Source As String

Property Value

String

The name of the provider that generated the error.

Examples

The following example displays each SqlError within the SqlErrorCollection collection.

public void DisplaySqlErrors(SqlException exception)
{
    for (int i = 0; i < exception.Errors.Count; i++)
    {
        Console.WriteLine("Index #" + i + "\n" +
            "Source: " + exception.Errors[i].Source + "\n" +
            "Number: " + exception.Errors[i].Number.ToString() + "\n" +
            "State: " + exception.Errors[i].State.ToString() + "\n" +
            "Class: " + exception.Errors[i].Class.ToString() + "\n" +
            "Server: " + exception.Errors[i].Server + "\n" +
            "Message: " + exception.Errors[i].Message + "\n" +
            "Procedure: " + exception.Errors[i].Procedure + "\n" +
            "LineNumber: " + exception.Errors[i].LineNumber.ToString());
    }
    Console.ReadLine();
}

Public Sub DisplaySqlErrors(ByVal exception As SqlException)
    Dim i As Integer

    For i = 0 To exception.Errors.Count - 1
        Console.WriteLine(("Index #" & i & ControlChars.NewLine & _
            "Source: " & exception.Errors(i).Source & ControlChars.NewLine & _
            "Number: " & exception.Errors(i).Number.ToString() & ControlChars.NewLine & _
            "State: " & exception.Errors(i).State.ToString() & ControlChars.NewLine & _
            "Class: " & exception.Errors(i).Class.ToString() & ControlChars.NewLine & _
            "Server: " & exception.Errors(i).Server & ControlChars.NewLine & _
            "Message: " & exception.Errors(i).Message & ControlChars.NewLine & _
            "Procedure: " & exception.Errors(i).Procedure & ControlChars.NewLine & _
            "LineNumber: " & exception.Errors(i).LineNumber.ToString()))
    Next i
    Console.ReadLine()
End Sub

See also

• ADO.NET Overview