DateTime.Subtraction Operator
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| Subtraction(DateTime, DateTime) |
Subtracts a specified date and time from another specified date and time and returns a time interval. |
| Subtraction(DateTime, TimeSpan) |
Subtracts a specified time interval from a specified date and time and returns a new date and time. |
- Source:
- DateTime.cs
- Source:
- DateTime.cs
- Source:
- DateTime.cs
Subtracts a specified date and time from another specified date and time and returns a time interval.
public:
static TimeSpan operator -(DateTime d1, DateTime d2);public static TimeSpan operator -(DateTime d1, DateTime d2);static member ( - ) : DateTime * DateTime -> TimeSpanPublic Shared Operator - (d1 As DateTime, d2 As DateTime) As TimeSpanParameters
- d1
- DateTime
The date and time value to subtract from (the minuend).
- d2
- DateTime
The date and time value to subtract (the subtrahend).
Returns
The time interval between d1 and d2; that is, d1 minus d2.
Examples
The following example demonstrates the Subtract method and the subtraction operator.
System::DateTime date1 = System::DateTime( 1996, 6, 3, 22, 15, 0 );
System::DateTime date2 = System::DateTime( 1996, 12, 6, 13, 2, 0 );
System::DateTime date3 = System::DateTime( 1996, 10, 12, 8, 42, 0 );
// diff1 gets 185 days, 14 hours, and 47 minutes.
System::TimeSpan diff1 = date2.Subtract( date1 );
// date4 gets 4/9/1996 5:55:00 PM.
System::DateTime date4 = date3.Subtract( diff1 );
// diff2 gets 55 days 4 hours and 20 minutes.
System::TimeSpan diff2 = date2 - date3;
// date5 gets 4/9/1996 5:55:00 PM.
System::DateTime date5 = date1 - diff2;
open System
let date1 = DateTime(1996, 6, 3, 22, 15, 0)
let date2 = DateTime(1996, 12, 6, 13, 2, 0)
let date3 = DateTime(1996, 10, 12, 8, 42, 0)
// diff1 gets 185 days, 14 hours, and 47 minutes.
let diff1 = date2.Subtract date1
// date4 gets 4/9/1996 5:55:00 PM.
let date4 = date3.Subtract diff1
// diff2 gets 55 days 4 hours and 20 minutes.
let diff2 = date2 - date3
// date5 gets 4/9/1996 5:55:00 PM.
let date5 = date1 - diff2
System.DateTime date1 = new System.DateTime(1996, 6, 3, 22, 15, 0);
System.DateTime date2 = new System.DateTime(1996, 12, 6, 13, 2, 0);
System.DateTime date3 = new System.DateTime(1996, 10, 12, 8, 42, 0);
// diff1 gets 185 days, 14 hours, and 47 minutes.
System.TimeSpan diff1 = date2.Subtract(date1);
// date4 gets 4/9/1996 5:55:00 PM.
System.DateTime date4 = date3.Subtract(diff1);
// diff2 gets 55 days 4 hours and 20 minutes.
System.TimeSpan diff2 = date2 - date3;
// date5 gets 4/9/1996 5:55:00 PM.
System.DateTime date5 = date1 - diff2;
Dim date1 As New System.DateTime(1996, 6, 3, 22, 15, 0)
Dim date2 As New System.DateTime(1996, 12, 6, 13, 2, 0)
Dim date3 As New System.DateTime(1996, 10, 12, 8, 42, 0)
Dim diff1 As System.TimeSpan
' diff1 gets 185 days, 14 hours, and 47 minutes.
diff1 = date2.Subtract(date1)
Dim date4 As System.DateTime
' date4 gets 4/9/1996 5:55:00 PM.
date4 = date3.Subtract(diff1)
Dim diff2 As System.TimeSpan
' diff2 gets 55 days 4 hours and 20 minutes.
diff2 = System.DateTime.op_Subtraction(date2, date3)
Dim date5 As System.DateTime
' date5 gets 4/9/1996 5:55:00 PM.
date5 = System.DateTime.op_Subtraction(date1, diff2)
Remarks
The Subtraction(DateTime, DateTime) method does not consider the value of the Kind property of the two DateTime values when performing the subtraction. Before subtracting DateTime objects, ensure that the objects represent times in the same time zone. Otherwise, the result will include the difference between time zones.
Note
The DateTimeOffset.Subtraction(DateTimeOffset, DateTimeOffset) method does consider the difference between time zones when performing the subtraction.
The equivalent method for this operator is DateTime.Subtract(DateTime)
See also
Applies to
.NET 10 and other versions
| Product | Versions |
|---|---|
| .NET | Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9, 10 |
| .NET Framework | 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
| .NET Standard | 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 2.0, 2.1 |
| UWP | 10.0 |
- Source:
- DateTime.cs
- Source:
- DateTime.cs
- Source:
- DateTime.cs
Subtracts a specified time interval from a specified date and time and returns a new date and time.
public:
static DateTime operator -(DateTime d, TimeSpan t);public static DateTime operator -(DateTime d, TimeSpan t);static member ( - ) : DateTime * TimeSpan -> DateTimePublic Shared Operator - (d As DateTime, t As TimeSpan) As DateTimeParameters
- d
- DateTime
The date and time value to subtract from.
- t
- TimeSpan
The time interval to subtract.
Returns
An object whose value is the value of d minus the value of t.
Exceptions
The resulting DateTime is less than DateTime.MinValue or greater than DateTime.MaxValue.
Examples
The following example demonstrates the Subtract method and the subtraction operator.
System::DateTime date1 = System::DateTime( 1996, 6, 3, 22, 15, 0 );
System::DateTime date2 = System::DateTime( 1996, 12, 6, 13, 2, 0 );
System::DateTime date3 = System::DateTime( 1996, 10, 12, 8, 42, 0 );
// diff1 gets 185 days, 14 hours, and 47 minutes.
System::TimeSpan diff1 = date2.Subtract( date1 );
// date4 gets 4/9/1996 5:55:00 PM.
System::DateTime date4 = date3.Subtract( diff1 );
// diff2 gets 55 days 4 hours and 20 minutes.
System::TimeSpan diff2 = date2 - date3;
// date5 gets 4/9/1996 5:55:00 PM.
System::DateTime date5 = date1 - diff2;
open System
let date1 = DateTime(1996, 6, 3, 22, 15, 0)
let date2 = DateTime(1996, 12, 6, 13, 2, 0)
let date3 = DateTime(1996, 10, 12, 8, 42, 0)
// diff1 gets 185 days, 14 hours, and 47 minutes.
let diff1 = date2.Subtract date1
// date4 gets 4/9/1996 5:55:00 PM.
let date4 = date3.Subtract diff1
// diff2 gets 55 days 4 hours and 20 minutes.
let diff2 = date2 - date3
// date5 gets 4/9/1996 5:55:00 PM.
let date5 = date1 - diff2
System.DateTime date1 = new System.DateTime(1996, 6, 3, 22, 15, 0);
System.DateTime date2 = new System.DateTime(1996, 12, 6, 13, 2, 0);
System.DateTime date3 = new System.DateTime(1996, 10, 12, 8, 42, 0);
// diff1 gets 185 days, 14 hours, and 47 minutes.
System.TimeSpan diff1 = date2.Subtract(date1);
// date4 gets 4/9/1996 5:55:00 PM.
System.DateTime date4 = date3.Subtract(diff1);
// diff2 gets 55 days 4 hours and 20 minutes.
System.TimeSpan diff2 = date2 - date3;
// date5 gets 4/9/1996 5:55:00 PM.
System.DateTime date5 = date1 - diff2;
Dim date1 As New System.DateTime(1996, 6, 3, 22, 15, 0)
Dim date2 As New System.DateTime(1996, 12, 6, 13, 2, 0)
Dim date3 As New System.DateTime(1996, 10, 12, 8, 42, 0)
Dim diff1 As System.TimeSpan
' diff1 gets 185 days, 14 hours, and 47 minutes.
diff1 = date2.Subtract(date1)
Dim date4 As System.DateTime
' date4 gets 4/9/1996 5:55:00 PM.
date4 = date3.Subtract(diff1)
Dim diff2 As System.TimeSpan
' diff2 gets 55 days 4 hours and 20 minutes.
diff2 = System.DateTime.op_Subtraction(date2, date3)
Dim date5 As System.DateTime
' date5 gets 4/9/1996 5:55:00 PM.
date5 = System.DateTime.op_Subtraction(date1, diff2)
Remarks
This method subtracts the ticks value of t from the ticks value of d.
The equivalent method for this operator is DateTime.Subtract(DateTime)
See also
Applies to
.NET 10 and other versions
| Product | Versions |
|---|---|
| .NET | Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9, 10 |
| .NET Framework | 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
| .NET Standard | 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 2.0, 2.1 |
| UWP | 10.0 |
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