Double.Hypot(Double, Double) Method
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Computes the hypotenuse given two values representing the lengths of the shorter sides in a right-angled triangle.
public:
static double Hypot(double x, double y) = System::Numerics::IRootFunctions<double>::Hypot;public static double Hypot (double x, double y);static member Hypot : double * double -> doublePublic Shared Function Hypot (x As Double, y As Double) As DoubleParameters
- x
- Double
The value to square and add to y.
- y
- Double
The value to square and add to x.
Returns
The square root of x-squared plus y-squared.
Implements
Applies to
Collaborate with us on GitHub
The source for this content can be found on GitHub, where you can also create and review issues and pull requests. For more information, see our contributor guide.
Feedback
Coming soon: Throughout 2024 we will be phasing out GitHub Issues as the feedback mechanism for content and replacing it with a new feedback system. For more information see: https://aka.ms/ContentUserFeedback.
Submit and view feedback for