VisualStyleElement.ListView.Detail Class

Reference

Definition

Namespace:: System.Windows.Forms.VisualStyles

Assembly:: System.Windows.Forms.dll

Source:: VisualStyleElement.cs

Source:: VisualStyleElement.cs

Source:: VisualStyleElement.cs

Important

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Provides a VisualStyleElement for a list view in detail view. This class cannot be inherited.

public: ref class VisualStyleElement::ListView::Detail abstract sealed

public static class VisualStyleElement.ListView.Detail

type VisualStyleElement.ListView.Detail = class

Public Class VisualStyleElement.ListView.Detail

Inheritance: Object
VisualStyleElement.ListView.Detail

Examples

The following code example demonstrates how to create a VisualStyleRenderer with the VisualStyleElement returned by the Normal property. To run this example, paste it into a Windows Form. Handle the form's Paint event and call the DrawVisualStyleElementListViewDetail1 method from the Paint event-handling method, passing e as PaintEventArgs.

public void DrawVisualStyleElementListViewDetail1(PaintEventArgs e)
{
    if (VisualStyleRenderer.IsElementDefined(
        VisualStyleElement.ListView.Detail.Normal))
    {
        VisualStyleRenderer renderer =
             new VisualStyleRenderer(VisualStyleElement.ListView.Detail.Normal);
        Rectangle rectangle1 = new Rectangle(10, 50, 50, 50);
        renderer.DrawBackground(e.Graphics, rectangle1);
        e.Graphics.DrawString("VisualStyleElement.ListView.Detail.Normal",
             this.Font, Brushes.Black, new Point(10, 10));
    }
    else
        e.Graphics.DrawString("This element is not defined in the current visual style.",
             this.Font, Brushes.Black, new Point(10, 10));
}

Public Sub DrawVisualStyleElementListViewDetail1(ByVal e As PaintEventArgs)
    If (VisualStyleRenderer.IsElementDefined( _
     VisualStyleElement.ListView.Detail.Normal)) Then
        Dim renderer As New VisualStyleRenderer _
          (VisualStyleElement.ListView.Detail.Normal)
        Dim rectangle1 As New Rectangle(10, 50, 50, 50)
        renderer.DrawBackground(e.Graphics, rectangle1)
        e.Graphics.DrawString("VisualStyleElement.ListView.Detail.Normal", _
          Me.Font, Brushes.Black, New Point(10, 10))
    Else
        e.Graphics.DrawString("This element is not defined in the current visual style.", _
          Me.Font, Brushes.Black, New Point(10, 10))
    End If
End Sub

Remarks

The Normal property of the VisualStyleElement.ListView.Detail class returns a VisualStyleElement that represents a list view in detail view.

Properties

Normal

Gets a visual style element that represents a list view in detail view.

Applies to

Product	Versions
.NET Framework	2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
Windows Desktop	3.0, 3.1, 5, 6, 7, 8, 9, 10

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