ContainerControl.IContainerControl.ActivateControl(Control) Metodo
Importante
Alcune informazioni sono relative alla release non definitiva del prodotto, che potrebbe subire modifiche significative prima della release definitiva. Microsoft non riconosce alcuna garanzia, espressa o implicita, in merito alle informazioni qui fornite.
Attiva il controllo specificato.
virtual bool System.Windows.Forms.IContainerControl.ActivateControl(System::Windows::Forms::Control ^ control) = System::Windows::Forms::IContainerControl::ActivateControl;C#
bool IContainerControl.ActivateControl (System.Windows.Forms.Control control);abstract member System.Windows.Forms.IContainerControl.ActivateControl : System.Windows.Forms.Control -> bool
override this.System.Windows.Forms.IContainerControl.ActivateControl : System.Windows.Forms.Control -> boolFunction ActivateControl (control As Control) As Boolean Implements IContainerControl.ActivateControltrue se il controllo viene attivato con successo; in caso contrario, false.
Nell'esempio di codice seguente viene illustrato come ereditare dalla classe e implementare l'interfaccia ScrollableControl IContainerControl . L'implementazione ActiveControl viene aggiunta alla proprietà e al ActivateControl metodo .
using namespace System;
using namespace System::Windows::Forms;
using namespace System::Drawing;
public ref class MyContainer: public ScrollableControl, public IContainerControl
{
private:
Control^ activeControl;
public:
MyContainer()
{
// Make the container control Blue so it can be distinguished on the form.
this->BackColor = Color::Blue;
// Make the container scrollable.
this->AutoScroll = true;
}
property Control^ ActiveControl
{
// Add implementation to the IContainerControl.ActiveControl property.
virtual Control^ get()
{
return activeControl;
}
virtual void set( Control^ value )
{
// Make sure the control is a member of the ControlCollection.
if ( this->Controls->Contains( value ) )
{
activeControl = value;
}
}
}
// Add implementations to the IContainerControl.ActivateControl(Control) method.
virtual bool ActivateControl( Control^ active )
{
if ( this->Controls->Contains( active ) )
{
// Select the control and scroll the control into view if needed.
active->Select( );
this->ScrollControlIntoView( active );
this->activeControl = active;
return true;
}
return false;
}
};
C#
using System;
using System.Windows.Forms;
using System.Drawing;
public class MyContainer : ScrollableControl, IContainerControl
{
private Control activeControl;
public MyContainer()
{
// Make the container control Blue so it can be distinguished on the form.
this.BackColor = Color.Blue;
// Make the container scrollable.
this.AutoScroll = true;
}
// Add implementation to the IContainerControl.ActiveControl property.
public Control ActiveControl
{
get
{
return activeControl;
}
set
{
// Make sure the control is a member of the ControlCollection.
if(this.Controls.Contains(value))
{
activeControl = value;
}
}
}
// Add implementations to the IContainerControl.ActivateControl(Control) method.
public bool ActivateControl(Control active)
{
if(this.Controls.Contains(active))
{
// Select the control and scroll the control into view if needed.
active.Select();
this.ScrollControlIntoView(active);
this.activeControl = active;
return true;
}
return false;
}
}
Imports System.Windows.Forms
Imports System.Drawing
Public Class MyContainerControl
Inherits ScrollableControl
Implements IContainerControl
Private myActiveControl As Control
Public Sub New()
' Make the container control Blue so it can be distinguished on the form.
Me.BackColor = Color.Blue
' Make the container scrollable.
Me.AutoScroll = True
End Sub
' Add implementation to the IContainerControl.ActiveControl property.
Public Property ActiveControl() As Control Implements IContainerControl.ActiveControl
Get
Return Me.myActiveControl
End Get
Set
' Make sure the control is a member of the ControlCollection.
If Me.Controls.Contains(value) Then
Me.myActiveControl = value
End If
End Set
End Property
' Add implementation to the IContainerControl.ActivateControl(Control) method.
public Function ActivateControl(active As Control) As Boolean Implements IContainerControl.ActivateControl
If Me.Controls.Contains(active) Then
' Select the control and scroll the control into view if needed.
active.Select()
Me.ScrollControlIntoView(active)
Me.myActiveControl = active
Return True
End If
Return False
End Function
End Class
Il control parametro deve essere figlio del controllo contenitore.
| Prodotto | Versioni |
|---|---|
| .NET Framework | 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8 |
| Windows Desktop | 3.0, 3.1, 5, 6, 7 |