# Double.MinValue 필드

## 정의

Double의 최소값을 나타냅니다. 이 필드는 상수입니다.

public: double MinValue = -1.7976931348623157E+308;
public const double MinValue = -1.7976931348623157E+308;
val mutable MinValue : double
Public Const MinValue As Double  = -1.7976931348623157E+308

#### 필드 값

Value = -1.7976931348623157E+308

## 예제

다음 코드 예제에서는 의 Double.MinValue사용을 보여 줍니다.

public ref class Temperature
{
public:
static property double MinValue
{
double get()
{
return Double::MinValue;
}
}

static property double MaxValue
{
double get()
{
return Double::MaxValue;
}
}

protected:
// The value holder
double m_value;

public:
property double Value
{
double get()
{
return m_value;
}
void set( double value )
{
m_value = value;
}
}

property double Celsius
{
double get()
{
return (m_value - 32.0) / 1.8;
}
void set( double value )
{
m_value = 1.8 * value + 32.0;
}
}
};

public class Temperature {
public static double MinValue {
get {
return Double.MinValue;
}
}

public static double MaxValue {
get {
return Double.MaxValue;
}
}

// The value holder
protected double m_value;

public double Value {
get {
return m_value;
}
set {
m_value = value;
}
}

public double Celsius {
get {
return (m_value-32.0)/1.8;
}
set {
m_value = 1.8*value+32.0;
}
}
}

type Temperature() =
static member MinValue =
Double.MinValue

static member MaxValue =
Double.MaxValue

member val Value = 0. with get, set

member this.Celsius
with get () =
(this.Value - 32.) / 1.8
and set (value) =
this.Value <- 1.8 * value + 32.

Public Class Temperature

Public Shared ReadOnly Property MinValue() As Double
Get
Return Double.MinValue
End Get
End Property

Public Shared ReadOnly Property MaxValue() As Double
Get
Return Double.MaxValue
End Get
End Property

' The value holder
Protected m_value As Double

Public Property Value() As Double
Get
Return m_value
End Get
Set(ByVal Value As Double)
m_value = Value
End Set
End Property

Public Property Celsius() As Double
Get
Return (m_value - 32) / 1.8
End Get
Set(ByVal Value As Double)
m_value = Value * 1.8 + 32
End Set
End Property
End Class


## 설명

이 상수의 값은 음수 1.7976931348623157E+308입니다.

보다 Double.MinValue 작은 작업의 결과는 입니다 Double.NegativeInfinity. 다음 예제 Double.NegativeInfinity 에서는 결과가 보다 Double.MinValue작을 때 빼기 및 곱하기 작업의 결과를 반환합니다.

using System;

public class Example
{
public static void Main()
{
double result1 = -7.997e307 + -9.985e307;
Console.WriteLine("{0} (Negative Infinity: {1})",
result1, Double.IsNegativeInfinity(result1));

double result2 = -1.5935e250 * 7.948e110;
Console.WriteLine("{0} (Negative Infinity: {1})",
result2, Double.IsNegativeInfinity(result2));
}
}
// The example displays the following output:
//    -Infinity (Negative Infinity: True)
//    -Infinity (Negative Infinity: True)

open System

let result1 = -7.997e307 + -9.985e307
printfn $"{result1} (Negative Infinity: {Double.IsNegativeInfinity result1})" let result2 = -1.5935e250 * 7.948e110 printfn$"{result2} (Negative Infinity: {Double.IsNegativeInfinity result2})"
// The example displays the following output:
//    -Infinity (Negative Infinity: True)
//    -Infinity (Negative Infinity: True)

Module Example
Public Sub Main()
Dim result1 As Double = -7.997e307 + -9.985e307
Console.WriteLine("{0} (Negative Infinity: {1})",
result1, Double.IsNegativeInfinity(result1))

Dim result2 As Double = -1.5935e250 * 7.948e110
Console.WriteLine("{0} (Negative Infinity: {1})",
result2, Double.IsNegativeInfinity(result2))
End Sub
End Module
' The example displays the following output:
'    -Infinity (Negative Infinity: True)
'    -Infinity (Negative Infinity: True)