IUIService.ShowToolWindow(Guid) Method

Reference

Definition

Namespace:: System.Windows.Forms.Design

Assembly:: System.Windows.Forms.dll

Source:: IUIService.cs

Source:: IUIService.cs

Source:: IUIService.cs

Important

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Displays the specified tool window.

public:
 bool ShowToolWindow(Guid toolWindow);

public bool ShowToolWindow(Guid toolWindow);

abstract member ShowToolWindow : Guid -> bool

Public Function ShowToolWindow (toolWindow As Guid) As Boolean

Parameters

toolWindow: Guid

A Guid identifier for the tool window. This can be a custom Guid or one of the predefined values from StandardToolWindows.

Returns

Boolean

true if the tool window was successfully shown; false if it could not be shown or found.

Examples

The following code example attempts to obtain an instance of the IUIService and invoke the service's ShowToolWindow method.

IUIService^ UIservice = dynamic_cast<IUIService^>(this->GetService( System::Windows::Forms::Design::IUIService::typeid ));
if ( UIservice != nullptr )
      UIservice->ShowToolWindow( StandardToolWindows::TaskList );

IUIService UIservice = (IUIService)this.GetService( 
    typeof( System.Windows.Forms.Design.IUIService ) );
if( UIservice != null )            
    UIservice.ShowToolWindow(StandardToolWindows.TaskList);

Dim UIservice As IUIService = CType(Me.GetService( _
    GetType(System.Windows.Forms.Design.IUIService)), IUIService)
If (UIservice IsNot Nothing) Then
    UIservice.ShowToolWindow(StandardToolWindows.TaskList)
End If

Applies to

ผลิตภัณฑ์	เวอร์ชัน
.NET Framework	1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
Windows Desktop	3.0, 3.1, 5, 6, 7, 8, 9, 10

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