Читати англійською Редагувати

Поділитися через


DateTimeFormatInfo.DateSeparator Property

Definition

Gets or sets the string that separates the components of a date, that is, the year, month, and day.

C#
public string DateSeparator { get; set; }

Property Value

The string that separates the components of a date, that is, the year, month, and day. The default for InvariantInfo is "/".

Exceptions

The property is being set to null.

The property is being set and the DateTimeFormatInfo object is read-only.

Examples

The following example instantiates a CultureInfo object for the en-US culture, changes its date separator to "-", and displays a date by using the "d", "G", and "g" standard format strings.

C#
using System;
using System.Globalization;

public class Example
{
   public static void Main()
   {
      DateTime value = new DateTime(2013, 9, 8);

      string[] formats = { "d", "G", "g" };
      CultureInfo culture = CultureInfo.CreateSpecificCulture("en-US");
      DateTimeFormatInfo dtfi = culture.DateTimeFormat;
      dtfi.DateSeparator = "-";

      foreach (var fmt in formats)
         Console.WriteLine("{0}: {1}", fmt, value.ToString(fmt, dtfi));
   }
}
// The example displays the following output:
//       d: 9-8-2013
//       G: 9-8-2013 12:00:00 AM
//       g: 9-8-2013 12:00 AM

Remarks

If a custom format string includes the "/" format specifier, the DateTime.ToString method displays the value of DateSeparator in place of the "/" in the result string.

The DateSeparator property defines the string that replaces the date separator ("/" custom date and time format specifier) in a result string in a formatting operation. It also defines the date separator string in a parsing operation.

Applies to

Продукт Версії
.NET Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9, 10
.NET Framework 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 2.0, 2.1

See also