VisualStyleElement.TreeView.Branch Class

Reference

Definition

Namespace:: System.Windows.Forms.VisualStyles

Assembly:: System.Windows.Forms.dll

Source:: VisualStyleElement.cs

Source:: VisualStyleElement.cs

Source:: VisualStyleElement.cs

Important

Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.

Provides a VisualStyleElement for a tree view branch. This class cannot be inherited.

public: ref class VisualStyleElement::TreeView::Branch abstract sealed

public static class VisualStyleElement.TreeView.Branch

type VisualStyleElement.TreeView.Branch = class

Public Class VisualStyleElement.TreeView.Branch

Inheritance: Object
VisualStyleElement.TreeView.Branch

Examples

The following code example demonstrates how to create a VisualStyleRenderer with the VisualStyleElement returned by the Normal property. To run this example, paste it into a Windows Form. Handle the form's Paint event and call the DrawVisualStyleElementTreeViewBranch1 method from the Paint event-handling method, passing e as PaintEventArgs.

public void DrawVisualStyleElementTreeViewBranch1(PaintEventArgs e)
{
    if (VisualStyleRenderer.IsElementDefined(
        VisualStyleElement.TreeView.Branch.Normal))
    {
        VisualStyleRenderer renderer =
             new VisualStyleRenderer(VisualStyleElement.TreeView.Branch.Normal);
        Rectangle rectangle1 = new Rectangle(10, 50, 50, 50);
        renderer.DrawBackground(e.Graphics, rectangle1);
        e.Graphics.DrawString("VisualStyleElement.TreeView.Branch.Normal",
             this.Font, Brushes.Black, new Point(10, 10));
    }
    else
        e.Graphics.DrawString("This element is not defined in the current visual style.",
             this.Font, Brushes.Black, new Point(10, 10));
}

Public Sub DrawVisualStyleElementTreeViewBranch1(ByVal e As PaintEventArgs)
    If (VisualStyleRenderer.IsElementDefined( _
     VisualStyleElement.TreeView.Branch.Normal)) Then
        Dim renderer As New VisualStyleRenderer _
          (VisualStyleElement.TreeView.Branch.Normal)
        Dim rectangle1 As New Rectangle(10, 50, 50, 50)
        renderer.DrawBackground(e.Graphics, rectangle1)
        e.Graphics.DrawString("VisualStyleElement.TreeView.Branch.Normal", _
          Me.Font, Brushes.Black, New Point(10, 10))
    Else
        e.Graphics.DrawString("This element is not defined in the current visual style.", _
          Me.Font, Brushes.Black, New Point(10, 10))
    End If
End Sub

Remarks

The Normal property of the VisualStyleElement.TreeView.Branch class returns a VisualStyleElement that represents a branch of a tree view control.

Properties

Normal

Gets a visual style element that represents a tree view branch.

Applies to

Продукт	Версії
.NET Framework	2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
Windows Desktop	3.0, 3.1, 5, 6, 7, 8, 9, 10

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