Double.IsInfinity(Double) 方法

定义

返回一个值,该值指示指定数字是计算为负无穷大还是正无穷大。

public:
 static bool IsInfinity(double d);
public:
 static bool IsInfinity(double d) = System::Numerics::INumberBase<double>::IsInfinity;
public static bool IsInfinity (double d);
static member IsInfinity : double -> bool
Public Shared Function IsInfinity (d As Double) As Boolean

参数

d
Double

一个双精度浮点数。

返回

如果 d 的计算结果为 PositiveInfinityNegativeInfinity,则为 true;否则为 false

实现

示例

以下代码示例演示了 的用法 IsInfinity

// This will return S"true".
Console::WriteLine( "IsInfinity(3.0 / 0) == {0}.", Double::IsInfinity( 3.0 / zero ) ? (String^)"true" : "false" );
// This will return "true".
Console.WriteLine("IsInfinity(3.0 / 0) == {0}.", Double.IsInfinity(3.0 / 0) ? "true" : "false");
// This will return "true".
printfn $"IsInfinity(3.0 / 0) = %b{Double.IsInfinity(3. / 0.)}."
' This will return "True".
Console.Write("IsInfinity(3.0 / 0) = ")
If Double.IsPositiveInfinity(3 / 0) Then
    Console.WriteLine("True.")
Else
    Console.WriteLine("False.")
End If

注解

浮点运算返回 PositiveInfinityNegativeInfinity 以发出溢出条件的信号。

适用于

另请参阅