共用方式為


Complex.Acos(Complex) 方法

定義

傳回角度,這個角度是指定複數的弧線餘弦值。

public:
 static System::Numerics::Complex Acos(System::Numerics::Complex value);
public static System.Numerics.Complex Acos (System.Numerics.Complex value);
static member Acos : System.Numerics.Complex -> System.Numerics.Complex
Public Shared Function Acos (value As Complex) As Complex

參數

value
Complex

代表餘弦的複數。

傳回

以弧度測量的角度,這是 value的弧度餘弦值。

範例

下列範例說明 Acos 方法。 它會顯示將 Acos 方法傳回的值傳遞至 Cos 方法會傳回原始 Complex 值。

using System;
using System.Numerics;

public class Example
{
   public static void Main()
   {
      Complex[] values = { new Complex(.5, 2),
                           new Complex(.5, -2),
                           new Complex(-.5, 2),
                           new Complex(-.3, -.8) };
      foreach (Complex value in values)
         Console.WriteLine("Cos(ACos({0})) = {1}", value,
                           Complex.Cos(Complex.Acos(value)));
   }
}
// The example displays the following output:
//       Cos(ACos((0.5, 2))) = (0.5, 2)
//       Cos(ACos((0.5, -2))) = (0.5, -2)
//       Cos(ACos((-0.5, 2))) = (-0.5, 2)
//       Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)
open System.Numerics

let values =
    [ Complex(0.5, 2.); Complex(0.5, -2.); Complex(-0.5, 2.); Complex(-0.3, -0.8) ]

for value in values do
    printfn $"Cos(ACos({value})) = {Complex.Acos value |> Complex.Cos}"
// The example displays the following output:
//       Cos(ACos((0.5, 2))) = (0.5, 2)
//       Cos(ACos((0.5, -2))) = (0.5, -2)
//       Cos(ACos((-0.5, 2))) = (-0.5, 2)
//       Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)
Imports System.Numerics

Module Example
   Public Sub Main()
      Dim values() As Complex = { New Complex(.5, 2), 
                                  New Complex(.5, -2),
                                  New Complex(-.5, 2),
                                  New Complex(-.3, -.8) }
      For Each value As Complex In values
         Console.WriteLine("Cos(ACos({0})) = {1}", value, 
                           Complex.Cos(Complex.Acos(value)))
      Next
   End Sub
End Module
' The example displays the following output:
'       Cos(ACos((0.5, 2))) = (0.5, 2)
'       Cos(ACos((0.5, -2))) = (0.5, -2)
'       Cos(ACos((-0.5, 2))) = (-0.5, 2)
'       Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)

備註

複數 Acos 方法會對應至實數的 Math.Acos 方法。

Acos 方法會使用下列公式:

(-ImaginaryOne) * Log(value + ImaginaryOne * Sqrt(One - value * value))

適用於

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