regexp_substr
function
Applies to: Databricks SQL Databricks Runtime 11.3 LTS and above
Returns the first substring in str
that matches regexp
.
Syntax
regexp_substr( str, regexp )
Arguments
str
: ASTRING
expression to be matched.regexp
: ASTRING
expression with a pattern.
Returns
A STRING
.
The regexp
string must be a Java regular expression.
String literals are unescaped. For example, to match '\abc'
, a regular expression for regexp
can be '^\\abc$'
.
In case of a malformed regexp
the function returns an INVALID_PARAMETER_VALUE error.
If either argument is NULL
or the pattern is not found, the result is NULL
.
Examples
> SELECT regexp_substr('Steven Jones and Stephen Smith are the best players', 'Ste(v|ph)en');
Steven
> SELECT regexp_substr('Mary had a little lamb', 'Ste(v|ph)en');
NULL
> SELECT regexp_substr(NULL, 'Ste(v|ph)en');
NULL
> SELECT regexp_substr('Mary had a little lamb', NULL);
NULL