Table.PositionOf

Syntax

Table.PositionOf(table as table, row as record, optional occurrence as any, optional equationCriteria as any) as any

About

Returns the row position of the first occurrence of the row in the table specified. Returns -1 if no occurrence is found.

• table: The input table.
• row: The row in the table to find the position of.
• occurrence: [Optional] Specifies which occurrences of the row to return.
• equationCriteria: [Optional] Controls the comparison between the table rows.

Example 1

Find the position of the first occurrence of [a = 2, b = 4] in the table ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}).

Usage

Power Query M

Table.PositionOf(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 1, b = 4],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    [a = 2, b = 4]
)

Output

0

Example 2

Find the position of the second occurrence of [a = 2, b = 4] in the table ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}).

Usage

Power Query M

Table.PositionOf(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 1, b = 4],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    [a = 2, b = 4],
    1
)

Output

2

Example 3

Find the position of all the occurrences of [a = 2, b = 4] in the table ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}).

Usage

Power Query M

Table.PositionOf(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 1, b = 4],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    [a = 2, b = 4],
    Occurrence.All
)

Output

{0, 2}

Related content

Equation criteria