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SheetView.View Eigenschaft

Definition

Ansichtstyp

Stellt das folgende Attribut im Schema dar: view

[DocumentFormat.OpenXml.SchemaAttr(0, "view")]
public DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.Spreadsheet.SheetViewValues> View { get; set; }
public DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.Spreadsheet.SheetViewValues> View { get; set; }
[DocumentFormat.OpenXml.SchemaAttr(0, "view")]
public DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.Spreadsheet.SheetViewValues>? View { get; set; }
[DocumentFormat.OpenXml.SchemaAttr("view")]
public DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.Spreadsheet.SheetViewValues>? View { get; set; }
public DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.Spreadsheet.SheetViewValues>? View { get; set; }
member this.View : DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.Spreadsheet.SheetViewValues> with get, set
[<DocumentFormat.OpenXml.SchemaAttr(0, "view")>]
member this.View : DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.Spreadsheet.SheetViewValues> with get, set
[<DocumentFormat.OpenXml.SchemaAttr("view")>]
member this.View : DocumentFormat.OpenXml.EnumValue<DocumentFormat.OpenXml.Spreadsheet.SheetViewValues> with get, set
Public Property View As EnumValue(Of SheetViewValues)

Eigenschaftswert

Gibt zurück EnumValue<T>.

Attribute

Gilt für: