CurrentRunStatus-Eigenschaft
Gets the current execution status of the job.
Namespace: Microsoft.SqlServer.Management.Smo.Agent
Assembly: Microsoft.SqlServer.Smo (in Microsoft.SqlServer.Smo.dll)
Syntax
'Declaration
<SfcPropertyAttribute(SfcPropertyFlags.None Or SfcPropertyFlags.Expensive Or SfcPropertyFlags.Standalone)> _
Public ReadOnly Property CurrentRunStatus As JobExecutionStatus
Get
'Usage
Dim instance As Job
Dim value As JobExecutionStatus
value = instance.CurrentRunStatus
[SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.Expensive|SfcPropertyFlags.Standalone)]
public JobExecutionStatus CurrentRunStatus { get; }
[SfcPropertyAttribute(SfcPropertyFlags::None|SfcPropertyFlags::Expensive|SfcPropertyFlags::Standalone)]
public:
property JobExecutionStatus CurrentRunStatus {
JobExecutionStatus get ();
}
[<SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.Expensive|SfcPropertyFlags.Standalone)>]
member CurrentRunStatus : JobExecutionStatus
function get CurrentRunStatus () : JobExecutionStatus
Eigenschaftswert
Typ: Microsoft.SqlServer.Management.Smo.Agent. . :: . .JobExecutionStatus
A JobExecutionStatus object value that specifies the current execution status of the job.
Beispiele
The following code example creates a new job and displays its status.
C#
Server srv = new Server("(local)");
Job jb = new Job(srv.JobServer, "Test Job");
jb.Create();
Console.WriteLine(jb.CurrentRunStatus);
PowerShell
$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$jb = new-object Microsoft.SqlServer.Management.Smo.Agent.Job($srv.JobServer, "Test Job")
$jb.Create()
Write-Host $jb.CurrentRunStatus
Siehe auch