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Returns information about a detached database file.
Namespace: Microsoft.SqlServer.Management.Smo
Assembly: Microsoft.SqlServer.Smo (in Microsoft.SqlServer.Smo.dll)
Syntax
'Declaration
Public Function DetachedDatabaseInfo ( _
mdfName As String _
) As DataTable
'Usage
Dim instance As Server
Dim mdfName As String
Dim returnValue As DataTable
returnValue = instance.DetachedDatabaseInfo(mdfName)
public DataTable DetachedDatabaseInfo(
string mdfName
)
public:
DataTable^ DetachedDatabaseInfo(
String^ mdfName
)
member DetachedDatabaseInfo :
mdfName:string -> DataTable
public function DetachedDatabaseInfo(
mdfName : String
) : DataTable
Parameter
- mdfName
Typ: System.String
A String value that specifies the detached database file.
Rückgabewert
Typ: System.Data.DataTable
A DataTable system object value that contains a list of information about a detached database file. The table describes the different columns of the returned DataTable.
Column |
Data type |
Description |
|---|---|---|
DatabaseName |
The name of the database. |
|
DatabaseVersion |
The version of the database. |
|
Collation |
The number of the collation that is used with the database. |
Beispiele
Visual Basic
'Connect to the local, default instance of SQL Server.
Dim srv As Server
srv = New Server
Dim owner As String
Dim logstr as String
Dim datastr as String
owner = srv.Databases("AdventureWorks2012").Owner
'Detach the AdventureWorks2012 database.
srv.DetachDatabase("AdventureWorks2012", False, False)
'Display information about the detached database.
Dim d As DataTable
Datastr = "C:\Program Files\Microsoft SQL Server"
Datastr = datastr + "\MSSQL10_50\MSSQL\Data\AdventureWorks2012_Data.mdf"
Logstr = "C:\Program Files\Microsoft SQL Server"
Logstr = datastr + "\MSSQL10_50\MSSQL\Data\AdventureWorks2012_Log.ldf"
d = srv.DetachedDatabaseInfo(datastr)
Dim r As DataRow
Dim c As DataColumn
For Each r In d.Rows
Console.WriteLine("==========================")
For Each c In r.Table.Columns
Console.WriteLine(c.ColumnName + " = " + r[c].ToString)
Next
Next
'Check whether the file is a detached primary file.
Console.WriteLine(srv.IsDetachedPrimaryFile(datastr))
'Attach the database
Dim sc As StringCollection
sc = New StringCollection
sc.Add(datastr)
sc.Add(logstr)
srv.AttachDatabase("AdventureWorks2012", sc, owner, AttachOptions.None)
PowerShell
$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = New-Object Microsoft.SqlServer.Management.Smo.Database
$db = $srv.Databases.Item("AdventureWorks2012")
$owner = $db.Owner
$srv.DetachDatabase("AdventureWorks2012", $FALSE, $FALSE)
$datastr = "C:\Program Files\Microsoft SQL Server"
$datastr = $datastr + "\MSSQL10_50\MSSQL\Data\AdventureWorks2012_Data.mdf"
$logstr = "C:\Program Files\Microsoft SQL Server"
$logstr = $logstr + "\MSSQL10_50\MSSQL\Data\AdventureWorks2012_Log.ldf"
$d = $srv.DetachedDatabaseInfo($datastr)
foreach ($r in $d.Rows)
{
Write-Host "=========================="
Foreach ($c in $d.Columns)
{
Write-Host $c.ColumnName "=" $r[$c].ToString()
}
}
Write-Host $srv.IsDetachedPrimaryFile($datastr)
$sc = new-object Systems.Collections.Specialized.StringCollection
$sc.Add($datastr)
$sc.Add($logstr)
$srv.AttachDatabase("AdventureWorks2012", $sc, $owner, [Microsoft.SqlServer.Management.Smo.AttachOptions]::None)
Siehe auch
Verweis
Microsoft.SqlServer.Management.Smo-Namespace