Freigeben über


Methods Constructor

When implemented in a derived class, initializes a new instance of the Methods class.

Namespace:  Microsoft.VisualStudio.Package
Assemblies:   Microsoft.VisualStudio.Package.LanguageService.9.0 (in Microsoft.VisualStudio.Package.LanguageService.9.0.dll)
  Microsoft.VisualStudio.Package.LanguageService.10.0 (in Microsoft.VisualStudio.Package.LanguageService.10.0.dll)
  Microsoft.VisualStudio.Package.LanguageService (in Microsoft.VisualStudio.Package.LanguageService.dll)
  Microsoft.VisualStudio.Package.LanguageService.12.0 (in Microsoft.VisualStudio.Package.LanguageService.12.0.dll)
  Microsoft.VisualStudio.Package.LanguageService.11.0 (in Microsoft.VisualStudio.Package.LanguageService.11.0.dll)

Syntax

'Declaration
Protected Sub New
protected Methods()
protected:
Methods()
new : unit -> Methods
protected function Methods()

Remarks

It is not necessary to call the base class constructor in your derived class.

.NET Framework Security

See Also

Reference

Methods Class

Microsoft.VisualStudio.Package Namespace