Grammar.Name Property
Definition
Important
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Gets or sets the name of a Grammar object.
public:
property System::String ^ Name { System::String ^ get(); void set(System::String ^ value); };
public string Name { get; set; }
member this.Name : string with get, set
Public Property Name As String
Property Value
The Name
property returns the name of the Grammar object. The default is null
.
Examples
The following example creates two Grammar objects, one for digits and one for fractions. The Grammar objects are assigned names and relative weights and priorities, and loaded by an in-process speech recognizer. The CreateDigitsGrammar
, CreateFractionsGrammar
, and recognizer_SpeechRecognized
methods are not shown here.
// Create a Grammar for recognizing numeric digits.
Grammar digitsGrammar = CreateDigitsGrammar();
digitsGrammar.Name = "Digits Grammar";
digitsGrammar.Priority = 2;
digitsGrammar.Weight = 0.6f;
// Create a Grammar for recognizing fractions.
Grammar fractionsGrammar = CreateFractionsGrammar();
fractionsGrammar.Name = "Fractions Grammar";
fractionsGrammar.Priority = 1;
fractionsGrammar.Weight = 1f;
// Create an in-process speech recognizer.
SpeechRecognitionEngine recognizer = new SpeechRecognitionEngine();
recognizer.SpeechRecognized +=
new EventHandler<SpeechRecognizedEventArgs>(
recognizer_SpeechRecognized);
// Load the digits and fractions Grammar objects.
recognizer.LoadGrammar(digitsGrammar);
recognizer.LoadGrammar(fractionsGrammar);
// Start recognition.
recognizer.SetInputToDefaultAudioDevice();
recognizer.RecognizeAsync(RecognizeMode.Multiple);
Applies to
See also
Σχόλια
https://aka.ms/ContentUserFeedback.
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