Vector.LessThanOrEqualAll<T>(Vector<T>, Vector<T>) Method
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Returns a value that indicates whether all elements in the first vector are less than or equal to their corresponding elements in the second vector.
public:
generic <typename T>
where T : value class static bool LessThanOrEqualAll(System::Numerics::Vector<T> left, System::Numerics::Vector<T> right);
public:
generic <typename T>
static bool LessThanOrEqualAll(System::Numerics::Vector<T> left, System::Numerics::Vector<T> right);
public static bool LessThanOrEqualAll<T> (System.Numerics.Vector<T> left, System.Numerics.Vector<T> right) where T : struct;
public static bool LessThanOrEqualAll<T> (System.Numerics.Vector<T> left, System.Numerics.Vector<T> right);
static member LessThanOrEqualAll : System.Numerics.Vector<'T (requires 'T : struct)> * System.Numerics.Vector<'T (requires 'T : struct)> -> bool (requires 'T : struct)
static member LessThanOrEqualAll : System.Numerics.Vector<'T> * System.Numerics.Vector<'T> -> bool
Public Shared Function LessThanOrEqualAll(Of T As Structure) (left As Vector(Of T), right As Vector(Of T)) As Boolean
Public Function LessThanOrEqualAll(Of T As Structure) (left As Vector(Of T), right As Vector(Of T)) As Boolean
Public Function LessThanOrEqualAll(Of T) (left As Vector(Of T), right As Vector(Of T)) As Boolean
Type Parameters
- T
The vector type. T
can be any primitive numeric type.
Parameters
- left
- Vector<T>
The first vector to compare.
- right
- Vector<T>
The second vector to compare.
Returns
true
if all of the elements in left
are less than or equal to the corresponding elements in right
; otherwise, false
.
Applies to
Collaborate with us on GitHub
The source for this content can be found on GitHub, where you can also create and review issues and pull requests. For more information, see our contributor guide.