Save Picturebox image to datagridview

Question

looking for a way to save an image to a datagridview cell, image is loaded into the picturebox then when form is closed saves it to the datagrid.

Answer 1

Hi, @Ben Ramsay ,Welcome to Microsoft Q&A,

Save the image to the 'DataGridView' cell and load and save it from the 'PictureBox' .

using System;
using System.Drawing;
using System.IO;
using System.Windows.Forms;

public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }

    private void Form1_Load(object sender, EventArgs e)
    {
        // Initialize DataGridView with an image column
        DataGridViewImageColumn imageColumn = new DataGridViewImageColumn();
        imageColumn.HeaderText = "Image";
        imageColumn.Name = "ImageColumn";
        dataGridView1.Columns.Add(imageColumn);
    }

    private void btnLoadImage_Click(object sender, EventArgs e)
    {
        // Load image into PictureBox
        OpenFileDialog openFileDialog = new OpenFileDialog();
        openFileDialog.Filter = "Image Files|*.jpg;*.jpeg;*.png;*.bmp";
        if (openFileDialog.ShowDialog() == DialogResult.OK)
        {
            pictureBox1.Image = Image.FromFile(openFileDialog.FileName);
        }
    }

    private void btnSaveToDataGrid_Click(object sender, EventArgs e)
    {
        // Save image from PictureBox to DataGridView
        if (pictureBox1.Image != null)
        {
            int rowIndex = dataGridView1.Rows.Add();
            dataGridView1.Rows[rowIndex].Cells["ImageColumn"].Value = pictureBox1.Image;
        }
    }

    private void Form1_FormClosing(object sender, FormClosingEventArgs e)
    {
        // Save DataGridView data when form is closing
        SaveDataGridViewImages();
    }

    private void SaveDataGridViewImages()
    {
        for (int i = 0; i < dataGridView1.Rows.Count; i++)
        {
            if (dataGridView1.Rows[i].Cells["ImageColumn"].Value != null)
            {
                Image image = (Image)dataGridView1.Rows[i].Cells["ImageColumn"].Value;
                string filePath = $"image_{i}.png"; // Save the image with a unique name
                image.Save(filePath);
            }
        }
    }
}

Best Regards,

Jiale

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