regex expression to find 40 charecters string of digits or lower/upper case latter starting only with 6 or H

Question

Hi,

i use [A-Za-z0-9]{40} to find the string with all possible charecters. now how can i force the regex to find just those begining with either digit 6 Or letter H ?

Thanks.

Answer 1

Try this expression: [6Hh][A-Za-z0-9]{39}.