How overload operator with function as parameter like endl in cout

Question

How overload operator with function as parameter like endl in cout in c++

I need on my project to do this. for example in following code

CSampleClass test;
test << CSampleClass::foo;

I writes code as following but cause error:

in class header file

CSampleClass& foo(CSampleClass& c);
CSampleClass& operator << (CSampleClass& (*pf)(CSampleClass&));

in class source file

CSampleClass& CSampleClass::foo(CSampleClass& c)
{
    // do some thing
    return *this;
}

CSampleClass& CSampleClass::operator << (CSampleClass& (*pf)(CSampleClass&))
{   
    return *pf(*this);
}

Thanks

Answer 1

This seems to work:

class CSampleClass
{
public:

    static CSampleClass& foo( CSampleClass& c )
    {
        // do some thing
        return c;
    }

    CSampleClass& operator << ( CSampleClass& ( *pf )( CSampleClass& ) )
    {
        return (*pf)( *this );
    }
};

. . .

CSampleClass test;
test << CSampleClass::foo;

Answer 2

class CSampleClass
{

public:
    static CSampleClass* m_pTHIS;

    CSampleClass()
    {
        m_pTHIS = this;
    }

    static CSampleClass& foo(CSampleClass& c)
    {
        m_pTHIS = &c;
        return *m_pTHIS;
    }

    CSampleClass& operator<< (CSampleClass& (*pf)(CSampleClass&))
    {
        return (*pf)(*m_pTHIS);
    }
};
CSampleClass* CSampleClass::m_pTHIS;

int main()
{
    CSampleClass test;

    test << CSampleClass::foo;
    return 0;
}