Displaying a WPF Window from ViewModel in C#

Question

I have a C#/WPF app based on MVVM pattern. The app has a window with a tool bar. On clicking a button on this toolbar, I need to show a Window like a settings window. The toolbar button is bound to a command that should load the settings window. I have designed the WPF settings window. The user will be able to select some settings(preferences) from this second window. This I understand is not like page navigation but loading the window. When the settings window is displayed the main window will be in the background. How I can I do this from the ViewModel of the main window?

Answer 1

Hi,
in ViewModel of Main window you can call ShowDialog with Settings window instance and bind the same ViewModel instance. Try following demo:

and ViewModel:

Namespace WpfApp048  
  Public Class ViewModel  
    Implements ICommand  
  
    Public Property Value1 As String  
  
    Public Event CanExecuteChanged As EventHandler Implements ICommand.CanExecuteChanged  
    Public Sub Execute(parameter As Object) Implements ICommand.Execute  
      Dim wndSetting = New Window048A  
      wndSetting.DataContext = Me  
      wndSetting.ShowDialog()  
    End Sub  
    Public Function CanExecute(parameter As Object) As Boolean Implements ICommand.CanExecute  
      Return True  
    End Function  
  End Class  
End Namespace