MethodBase.IsVirtual Property
Definition
Important
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Gets a value indicating whether the method is virtual
.
public:
property bool IsVirtual { bool get(); };
public bool IsVirtual { get; }
member this.IsVirtual : bool
Public ReadOnly Property IsVirtual As Boolean
Property Value
true
if this method is virtual
; otherwise, false
.
Implements
Examples
The following example displays false
for IsFinal
, which might lead you to think that MyMethod
is overridable. The code prints false
even though MyMethod
is not marked virtual
and thus cannot be overridden.
using namespace System;
using namespace System::Reflection;
public ref class MyClass
{
public:
void MyMethod(){}
};
int main()
{
MethodBase^ m = MyClass::typeid->GetMethod( "MyMethod" );
Console::WriteLine( "The IsFinal property value of MyMethod is {0}.", m->IsFinal );
Console::WriteLine( "The IsVirtual property value of MyMethod is {0}.", m->IsVirtual );
}
using System;
using System.Reflection;
public class MyClass
{
public void MyMethod()
{
}
public static void Main()
{
MethodBase m = typeof(MyClass).GetMethod("MyMethod");
Console.WriteLine("The IsFinal property value of MyMethod is {0}.", m.IsFinal);
Console.WriteLine("The IsVirtual property value of MyMethod is {0}.", m.IsVirtual);
}
}
Imports System.Reflection
Public Class MyClass1
Public Sub MyMethod()
End Sub
Public Shared Sub Main()
Dim m As MethodBase = GetType(MyClass1).GetMethod("MyMethod")
Console.WriteLine("The IsFinal property value of MyMethod is {0}.", m.IsFinal)
Console.WriteLine("The IsVirtual property value of MyMethod is {0}.", m.IsVirtual)
End Sub
End Class
Remarks
A virtual member may reference instance data in a class and must be referenced through an instance of the class.
To determine if a method is overridable, it is not sufficient to check that IsVirtual
is true
. For a method to be overridable, IsVirtual
must be true
and IsFinal must be false
. For example, a method might be non-virtual, but it implements an interface method. The common language runtime requires that all methods that implement interface members must be marked as virtual
; therefore, the compiler marks the method virtual final
. So there are cases where a method is marked as virtual
but is still not overridable.
To establish with certainty whether a method is overridable, use code such as this:
if (MethodInfo.IsVirtual && !MethodInfo.IsFinal)
If MethodInfo.IsVirtual AndAlso Not MethodInfo.IsFinal Then
If IsVirtual
is false
or IsFinal
is true
, then the method cannot be overridden.
You can determine whether the current method overrides a method in a base class by calling the MethodInfo.GetBaseDefinition method. The following example implements an IsOverride
method that does this.
using System;
using System.Reflection;
public class ReflectionUtilities
{
public static bool IsOverride(MethodInfo method)
{
return ! method.Equals(method.GetBaseDefinition());
}
}
public class Example
{
public static void Main()
{
MethodInfo equals = typeof(Int32).GetMethod("Equals",
new Type[] { typeof(Object) } );
Console.WriteLine("{0}.{1} is inherited: {2}",
equals.ReflectedType.Name, equals.Name,
ReflectionUtilities.IsOverride(equals));
equals = typeof(Object).GetMethod("Equals",
new Type[] { typeof(Object) } );
Console.WriteLine("{0}.{1} is inherited: {2}",
equals.ReflectedType.Name, equals.Name,
ReflectionUtilities.IsOverride(equals));
}
}
// The example displays the following output:
// Int32.Equals is inherited: True
// Object.Equals is inherited: False
Imports System.Reflection
Public Class ReflectionUtilities
Public Shared Function IsOverride(method As MethodInfo) As Boolean
Return Not method.Equals(method.GetBaseDefinition())
End Function
End Class
Module Example
Public Sub Main()
Dim equals As MethodInfo = GetType(Int32).GetMethod("Equals",
{ GetType(Object) } )
Console.WriteLine("{0}.{1} is inherited: {2}",
equals.ReflectedType.Name, equals.Name,
ReflectionUtilities.IsOverride(equals))
equals = GetType(Object).GetMethod("Equals", { GetType(Object) } )
Console.WriteLine("{0}.{1} is inherited: {2}",
equals.ReflectedType.Name, equals.Name,
ReflectionUtilities.IsOverride(equals))
End Sub
End Module
' The example displays the following output:
' Int32.Equals is inherited: True
' Object.Equals is inherited: False