Can C# detect exponents like 2² , 2³ not the ones with carets(^)

Question

Can C# detect exponents like 2² , 2³ not the ones with carets(^)

Kalyan A 440

Can C# detect exponents like 2² , 2³ not the ones with carets(^).

I want to detect 2³ and write Base =2 Exponent=3

The below code is from Copilot , It cannot detect 2²

using System;
using System.Text.RegularExpressions;
class Program
{
    static void Main()
    {
        string input = "The result of 2³ is eight.";
        Regex regex = new Regex(@"(\d+)\^(\d+)");
        Match match = regex.Match(input);
        if (match.Success)
        {
            int baseNum = int.Parse(match.Groups[1].Value);
            int exponent = int.Parse(match.Groups[2].Value);
            Console.WriteLine($"Base: {baseNum}, Exponent: {exponent}");
        }
        else
        {
            Console.WriteLine("No match found.");
        }
    }
}

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Answer 1

Viorel 122.6K

Try this:

string input = "The result of 2³ is eight.";
Regex regex = new Regex( @"(\d+)([\xB2\xB3\xB9\u2070\u2074-\u2079]+)" );
Match match = regex.Match( input );
if( match.Success )
{
    int baseNum = int.Parse( match.Groups[1].Value );
    int exponent = int.Parse( match.Groups[2].Value.Normalize( NormalizationForm.FormKC ) );
    Console.WriteLine( $"Base: {baseNum}, Exponent: {exponent}" );
}
else
{
    Console.WriteLine( "No match found." );
}

Kalyan A 440

This works

using System;
using System.Text;
using System.Text.RegularExpressions;
string input = "2³";
Regex regex = new Regex(@"(\d+)([\xB2\xB3\xB9\u2070\u2074-\u2079]+)");
Match match = regex.Match(input);
if (match.Success)
{
    int baseNum = int.Parse(match.Groups[1].Value);
    System.Console.WriteLine(baseNum);
   
   int exponent = int.Parse( match.Groups[2].Value.Normalize( NormalizationForm.FormKC ) );
    System.Console.WriteLine(exponent);
    
    
}
else
{
    Console.WriteLine("No match found.");
}

Bruce (SqlWork.com) 78,086 Volunteer Moderator

the sample code runs on .net fiddler. you issue is with int.Parse() handling superscript. you could just convert the superscript numbers to regular:

public static string convertSuper(string s)
{
	var scriptMapping = new Dictionary<char, char>() 
    {
		['¹'] = '1',
		['²'] = '2',
		['³'] = '3',
		['⁴'] = '4',
		['⁵'] = '5',
		['⁶'] = '6',
		['⁷'] = '7',
		['⁸'] = '8',
		['⁹'] = '9',
		['⁰'] = '0'
	};
	return new string(s.ToCharArray().Select(c => scriptMapping[c]).ToArray());	
}

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Can C# detect exponents like 2² , 2³ not the ones with carets(^)

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