remove values from string

Shambhu Rai 1,411 Reputation points
2022-08-17T10:50:23.187+00:00

Hi Expert,

how will i remove all the characters from values in sql

Create table test1
(id string, details string)

insert into test1
values('20kjk','3ddf')

Regards

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Accepted answer
  1. Yitzhak Khabinsky 25,956 Reputation points
    2022-08-17T12:58:16.167+00:00

    Hi @Shambhu Rai ,

    Please try the following solution. It will work starting from SQL Server 2017 onwards.

    SQL

    -- DDL and sample data population, start  
    DECLARE @tbl TABLE (ID INT IDENTITY PRIMARY KEY, details VARCHAR(100));  
    INSERT INTO @tbl values   
    ('20kjk'),  
    ('3ddf'),  
    ('561.456/.7890');  
    -- DDL and sample data population, end  
      
    -- SQL Server 2017 onwards  
    ;WITH rs AS   
    (  
       SELECT *  
          , REPLACE(TRANSLATE(details, '0123456789', SPACE(10)),' ','') AS JunkCharacters  
       FROM @tbl  
    )  
    SELECT rs.*  
       , REPLACE(TRANSLATE(details, TRIM(JunkCharacters), SPACE(LEN(TRIM(JunkCharacters)))),' ','') AS CleansedDetails  
    FROM rs;  
    

    Output

    +----+---------------+----------------+-----------------+  
    | ID |    details    | JunkCharacters | CleansedDetails |  
    +----+---------------+----------------+-----------------+  
    |  1 | 20kjk         | kjk            |              20 |  
    |  2 | 3ddf          | ddf            |               3 |  
    |  3 | 561.456/.7890 | ./.            |      5614567890 |  
    +----+---------------+----------------+-----------------+  
    
    1 person found this answer helpful.
    0 comments No comments

5 additional answers

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  1. Anurag Sharma 17,606 Reputation points
    2022-08-17T11:49:42.32+00:00

    Hi @Shambhu Rai , welcome to Microsoft Q&A platform.

    If the number always comes at the start, then you can use below:

    select LEFT('3ddf', PATINDEX('%[0-9][^0-9]%', '3ddf'))  
    

    You can also use the same in insert statement before inserting it to database:

    insert into test1  
        values(LEFT('20kjk', PATINDEX('%[0-9][^0-9]%', '20kjk' )) ,LEFT('3ddf', PATINDEX('%[0-9][^0-9]%', '3ddf' )))  
    

    Please let me know if this helps or else we can discuss further.

    Reference: split alpha and numeric using sql


  2. Alberto Morillo 34,056 Reputation points MVP
    2022-08-17T11:59:39.687+00:00

    Create this function:

    CREATE Function [fnRemoveNonNumericCharacters](@strText VARCHAR(1000))  
    RETURNS VARCHAR(1000)  
    AS  
    BEGIN  
        WHILE PATINDEX('%[^0-9]%', @strText) > 0  
        BEGIN  
            SET @strText = STUFF(@strText, PATINDEX('%[^0-9]%', @strText), 1, '')  
        END  
        RETURN @strText  
    END  
    

    then you can use it as shown below:

    CREATE TABLE test1  
    (id varchar(100), details varchar(100))  
      
    INSERT INTO test1  
    ([Id], [details])  
    SELECT dbo.fnRemoveNonNumericCharacters('20kjk'), dbo.fnRemoveNonNumericCharacters('3ddf')  
    
    0 comments No comments

  3. Isabellaz-1451 3,616 Reputation points
    2022-08-18T06:07:17.663+00:00

    Hi

    Please check a look at this thread,hope will help you.
    https://sqlzealots.com/2017/05/28/how-to-extract-only-numbers-from-a-string-in-sql-server/

    Best Regards,
    Isabella

    0 comments No comments

  4. LiHongMSFT-4306 28,351 Reputation points
    2022-08-18T08:53:16.023+00:00

    Hi @Shambhu Rai
    Have you tried the TRANSLATE function as Yitzhak answered? If your SQL Sever doesn't support this function, then you could have a try on looped REPLACE.
    Check this:

    DECLARE @tbl TABLE (ID INT IDENTITY PRIMARY KEY, details VARCHAR(100));  
    INSERT INTO @tbl values   
     ('20kjk'),  
     ('3ddf'),  
     ('ER78Y9'),  
     ('561.456/.7890');  
          
    SELECT *,   
           REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(  
    	   details,'0',''),'1',''),'2',''),'3',''),'4',''),'5',''),'6',''),'7',''),'8',''),'9','')AS New_Value  
    FROM @tbl  
    

    Best regards,
    LiHong

    0 comments No comments

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