Sorted number inside in the textbox

Question

Sorted number inside in the textbox

YUI-012 160

I want to sort the value of textbox1 automatically and display into textbox2.

I have a code but it not working properly. I insert this code into textbox2.

 private void textBox2_TextChanged(object sender, EventArgs e)
        {
			var count = default(int);
            if (int.TryParse(textBox1.Text, count))
            {
                string strNumbers = " ";
                for (int x = 0, loopTo = count - 1; x <= loopTo; x++)
                    strNumbers += x.ToString();
                textBox2.Text = strNumbers;
            }
        }

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Answer 1

Appreciate the clarification. It looks like you want to input numbers separated by spaces and have them sorted while maintaining leading zeros. If so, try the following:

private void textBox1_TextChanged(object sender, EventArgs e)
{
    // Read the input from textBox1 and split by spaces
    string input = textBox1.Text.Trim();
    string[] numbers = input.Split(new[] { ' ' }, StringSplitOptions.RemoveEmptyEntries);

    // Check if all elements are valid numbers
    if (numbers.All(n => int.TryParse(n, out _)))
    {
        // Sort numbers while preserving leading zeros
        var sortedNumbers = numbers.OrderBy(n => n).ToArray();

        // Join them back into a space-separated string
        textBox2.Text = string.Join(" ", sortedNumbers);
    }
    else
    {
        textBox2.Text = "Invalid input"; // Display error if input is not numeric
    }
}

If the above response helps answer your question, remember to "Accept Answer" so that others in the community facing similar issues can easily find the solution. Your contribution is highly appreciated.

hth

Marcin

YUI-012 160 Reputation points

2025-02-09T03:19:44.52+00:00

Marcin Policht, your code working properly. Thank you so much for your help.

Answer 2

There are a few issues with your code:

Wrong Event: You are using the TextChanged event of textBox2, but the logic should trigger when textBox1 changes.
Incorrect TryParse Usage: The second argument of int.TryParse should be an out parameter.
Sorting Issue: Your current code is not sorting anything; it generates numbers from 0 to count-1 instead.
Whitespace in Output: You are concatenating numbers as a string but leaving an unnecessary leading space.

Attach this event to textBox1.TextChanged instead:

private void textBox1_TextChanged(object sender, EventArgs e)
{
    if (int.TryParse(textBox1.Text, out int count))
    {
        // Generate a list of numbers from 1 to count
        List<int> numbers = new List<int>();
        for (int i = 1; i <= count; i++)
        {
            numbers.Add(i);
        }

        // Sort numbers (although it's naturally sorted)
        numbers.Sort();

        // Convert to a string and display in textBox2
        textBox2.Text = string.Join(", ", numbers);
    }
    else
    {
        textBox2.Text = "Invalid input";
    }
}

This code listens for changes in textBox1.
It tries to parse the integer value from textBox1.
It generates numbers from 1 to count, sorts them (though unnecessary here), and joins them into a string.
The result is displayed in textBox2.

If the above response helps answer your question, remember to "Accept Answer" so that others in the community facing similar issues can easily find the solution. Your contribution is highly appreciated.

hth

Marcin

YUI-012 160 Reputation points

2025-02-09T00:11:46.7233333+00:00

Marcin Policht, I try your program and its say "Invalid input".

I try to input 321 and it show long numbers.

Now I input 2 digit numbers 03 02 01 and it show Invalid input. My expectation is It will display the same 2 digit numbers but in sorted arrangement like 01 02 03.

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Sorted number inside in the textbox

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