Deserializing a JSON array string into a C# object

If your array continues with X4,Y4,Z4, you have a problem since, for deserializing the strong type class from the JSON, the array entries should be known. To deserialize the current JSON, use the following classes:

public class Rootobject
{
    public Class1[] Property1 { get; set; }
}

public class Class1
{
    public string X1 { get; set; }
    public string Y1 { get; set; }
    public string Z1 { get; set; }
    public string X2 { get; set; }
    public string Y2 { get; set; }
    public string Z2 { get; set; }
    public string X3 { get; set; }
    public string Y3 { get; set; }
    public string Z3 { get; set; }
}

You may read the JSON dynamically instead of deserializing the array:

    using System.Text.Json.Nodes;
    var jsonString = "[{\"X1\":\"x1\",\"Y1\":\"y1\",\"Z1\":\"z1\"},{\"X2\":\"x2\",\"Y2\":\"y2\",\"Z2\":\"z2\"},{\"X3\":\"x3\",\"Y3\":\"y3\",\"Z3\":\"z3\"}]";
    var jsonObject = JsonNode.Parse(jsonString);
    Console.WriteLine(jsonObject.ToString());
    Console.WriteLine(jsonObject[0]["X1"]);

Alon.

Hi @Julio Bello ,

[{"X1":"x1","Y1":"y1","Z1":"z1"},{"X2":"x2","Y2":"y2","Z2":"z2"},{"X3":"x3","Y3":"y3","Z3":"z3"},...]

From the above JSON string, we can see that each property (key-value pair, such as "X1":"x1", "X2":"x2") has a different property name or key value, in this scenario the property is not fixed so we can directly use it as the class's property.

So, for the above JSON string, I suggest you could deserialize it uses a Dictionary<string,string>, you can refer to the following sample code:

       //required using System.Text.Json;  

        var values = new List<Dictionary<string, string>>()  
        {  
              new Dictionary<string, string>()  
                {  
                    {"X1", "x1"},{"Y1", "Y1"},{"Z1", "Z1"}  
                },  
                  new Dictionary<string, string>()  
                {  
                    {"X2", "x2"},{"Y2", "Y2"},{"Z2", "Z2"}  
                }  
        };   
        var jsonstring = JsonSerializer.Serialize(values);  
        //jsonstring: [{"X1":"x1","Y1":"Y1","Z1":"Z1"},{"X2":"x2","Y2":"Y2","Z2":"Z2"}]  
        var reult1 = JsonSerializer.Deserialize<List<Dictionary<string, string>>>(jsonstring);  

        var test = new TestModel()  
        {  
            Item = new List<Dictionary<string, string>>()  
            {  
                new Dictionary<string, string>()  
                {  
                    {"X1", "x1"},{"Y1", "Y1"},{"Z1", "Z1"}  
                },  
                  new Dictionary<string, string>()  
                {  
                    {"X2", "x2"},{"Y2", "Y2"},{"Z2", "Z2"}  
                }  
            }  
        };  

        var jsonstring2 = JsonSerializer.Serialize(test);  
        //josnstring2: {"Item":[{"X1":"x1","Y1":"Y1","Z1":"Z1"},{"X2":"x2","Y2":"Y2","Z2":"Z2"}]}  

        var result2 = JsonSerializer.Deserialize<TestModel>(jsonstring2);  

The TestModel

public class TestModel  
{  
    public List<Dictionary<string, string>> Item { get; set; }  
}  

The output is like this:

And this sample code:

        var jsonstr = "[{\"X1\":\"x1\",\"Y1\":\"Y1\",\"Z1\":\"Z1\"},{\"X2\":\"x2\",\"Y2\":\"Y2\",\"Z2\":\"Z2\"}]";  

        var result3 = JsonSerializer.Deserialize<List<Dictionary<string, string>>>(jsonstr);  

The result:

After that you can find the data from the Dictionary. More detailed information about Dictionary, see Dictionary<TKey,TValue> Class

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Best regards,
Dillion