Take value based on line break sql

Hi @srk ,

Please try the following solution.

SQL

-- DDL and sample data population, start  
DECLARE @tbl TABLE (ID INT IDENTITY PRIMARY KEY, WorkAddress VARCHAR(MAX));  
INSERT INTO @tbl VALUES   
('89 Oliver''s Yard' + CHAR(13) +   
 '21 City Rd'+ CHAR(13) +   
 'London'+ CHAR(13) +   
 'EC1Y' + CHAR(13) + '1HP');  
-- DDL and sample data population, end  
  
DECLARE @separator CHAR(1) = CHAR(13);  
  
SELECT t.*  
 , c.value('(/root/r[1]/text())[1]', 'VARCHAR(30)') AS Address1  
 , c.value('(/root/r[2]/text())[1]', 'VARCHAR(30)') AS Street  
 , c.value('(/root/r[3]/text())[1]', 'VARCHAR(30)') AS City  
 , c.value('(/root/r[4]/text())[1]', 'VARCHAR(30)') + SPACE(1) +  
	c.value('(/root/r[5]/text())[1]', 'VARCHAR(30)') AS PostCode  
FROM @tbl AS t  
CROSS APPLY (SELECT TRY_CAST('<root><r><![CDATA[' +   
      REPLACE(WorkAddress, @separator, ']]></r><r><![CDATA[') +   
      ']]></r></root>' AS XML)) AS t1(c);  

Output

+----+---------------------------------------------+------------------+------------+--------+----------+  
| ID |                 WorkAddress                 |     Address1     |   Street   |  City  | POstCode |  
+----+---------------------------------------------+------------------+------------+--------+----------+  
|  1 | 89 Oliver's Yard 21 City Rd London EC1Y 1HP | 89 Oliver's Yard | 21 City Rd | London | EC1Y 1HP |  
+----+---------------------------------------------+------------------+------------+--------+----------+  

Hi，@srk

Welcome to Microsoft T-SQL Q&A Forum!

Try this:

create table #test  
 (  
 ID INT identity(1,1),  
 WorkAddress nvarchar(50)  
 )  
insert into #test values('89 Oliver''s Yard' + CHAR(13) + '21 City Rd'+ CHAR(13) + 'London'+ CHAR(13) +'EC1Y 1HP');  

 select * from #test  

 select   
 REVERSE(PARSENAME(REPLACE(REVERSE(WorkAddress ),  CHAR(13), '.'), 1)) AS [address1]  
    , REVERSE(PARSENAME(REPLACE(REVERSE(WorkAddress ),  CHAR(13), '.'), 2)) AS [street]  
    , REVERSE(PARSENAME(REPLACE(REVERSE(WorkAddress ),  CHAR(13), '.'), 3)) AS [city],  
    REVERSE(PARSENAME(REPLACE(REVERSE(WorkAddress ),  CHAR(13), '.'), 4)) AS [Postcode]  
 from #test  

]1
Best regards,
Bert Zhou

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 ;with mycte as (
SELECT id, '["'+ REPLACE(WorkAddress, CHAR(13), '","') + '"] ' jsCol
FROM test
)


select distinct id
,JSON_VALUE(jsCol, '$[0]') AS Address1 
,JSON_VALUE(jsCol, '$[1]') AS Street 
,JSON_VALUE(jsCol, '$[2]') AS City 
,JSON_VALUE(jsCol, '$[3]') AS Postcode 
FROM mycte
cross apply openjson(jsCol ) as j
 

Hi Bert,

Thanks for your reply ... it is not comma separated as its got line break between address1,street,city and postcode in workaddress column

I did notice the post code itself got line break so when we are giving '4' it is taking only first part. I would like to keep everything under postcode after 4th line break.

Please let me know

Many thanks in advance