How to run a C program that greeted only two users Alice and Bob. How to do it?

Question

I want to figure out this program that greet only two specific user and this program should not contain any string.

Answer 1

using System;

namespace GreetUsersWithoutStrings
{
    class Program
    {
        static int HashString(string s)
        {
            int hash = 0;
            foreach (char c in s)
            {
                hash += c;
            }
            return hash;
        }

        static void Main(string[] args)
        {
            int aliceHash = HashString("Alice");
            int bobHash = HashString("Bob");

            Console.Write("Enter your name: ");
            string inputName = Console.ReadLine();
            int inputHash = HashString(inputName);

            if (inputHash == aliceHash)
            {
                Console.WriteLine("Hello, Alice!");
            }
            else if (inputHash == bobHash)
            {
                Console.WriteLine("Hello, Bob!");
            }
            else
            {
                Console.WriteLine("Hello, stranger!");
            }
        }
    }
}

Answer 2

Hi Iqra Ahmed,

I wrote a sample for your reference, it cannot be executed directly, you need to modify it according to the actual situation.

void login_user(void)
{
	char name[20] = { 0 };
	char passwd[7] = { 0 };
	printf("enter user name：");
	gets(name);
	if (0 == strcmp("Alice", name))
	{//compare password
		printf("please input password：");
		gets(passwd);
		if (0 == strcmp(Alice password, passwd))
		{

			return;
		}
	}
	else if (0 == strcmp("Bob", name))
	{
			printf("please input password：");
			gets(passwd);
			if (0 == strcmp(Bob password, passwd))
			{

				return;
			}
	}
	else
	{
		printf("you are not alicec or bob");
		return;
	}	
}

This code mainly uses strcmp to determine whether the user is Alice or Bob, and it should be determined whether to execute the next step after the verification is passed.

Best regards,

Elya

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