How to call Form-recongnizer API version 2023-02-28 -layout model

Question

Do you have any sample code for me to call the API version 2023-02-28 - layout model to prcoess my data?

Answer 1

Hello @John Tsz Kin WONG (External) Thanks for reaching out to us, please be aware of that 2023-02-28-preview capabilities are currently only available in the following regions:

• West Europe
• West US2
• East US

I am sharing a Python sample for your reference, you can get sample in more languages at the bottom of the page - https://westus.dev.cognitive.microsoft.com/docs/services/form-recognizer-api-2023-02-28-preview/operations/AnalyzeDocument

########### Python 2.7 #############
import httplib, urllib, base64

headers = {
    # Request headers
    'Content-Type': 'application/json',
    'Ocp-Apim-Subscription-Key': '{subscription key}',
}

params = urllib.urlencode({
    # Request parameters
    'pages': '{string}',
    'locale': '{string}',
    'stringIndexType': 'textElements',
})

try:
    conn = httplib.HTTPSConnection('westus.api.cognitive.microsoft.com')
    conn.request("POST", "/formrecognizer/documentModels/{modelId}:analyze?api-version=2023-02-28-preview&%s" % params, "{body}", headers)
    response = conn.getresponse()
    data = response.read()
    print(data)
    conn.close()
except Exception as e:
    print("[Errno {0}] {1}".format(e.errno, e.strerror))

####################################

########### Python 3.2 #############
import http.client, urllib.request, urllib.parse, urllib.error, base64

headers = {
    # Request headers
    'Content-Type': 'application/json',
    'Ocp-Apim-Subscription-Key': '{subscription key}',
}

params = urllib.parse.urlencode({
    # Request parameters
    'pages': '{string}',
    'locale': '{string}',
    'stringIndexType': 'textElements',
})

try:
    conn = http.client.HTTPSConnection('westus.api.cognitive.microsoft.com')
    conn.request("POST", "/formrecognizer/documentModels/{modelId}:analyze?api-version=2023-02-28-preview&%s" % params, "{body}", headers)
    response = conn.getresponse()
    data = response.read()
    print(data)
    conn.close()
except Exception as e:
    print("[Errno {0}] {1}".format(e.errno, e.strerror))

####################################

More samples at the bottom -

I hope this helps. Regards, Yutong -Please kindly accept the answer and vote 'Yes' if you feel helpful to support the community, thanks a lot.