How to assign file content into variable as object

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How to assign file content into variable as object

Trần Ngọc Nam 35

I'm having problems like: First, I use

$localGroupMembers = Get-LocalGroupMember -Group $groupName -ErrorAction SilentlyContinue | Where-Object {$_.PrincipalSource -eq "Local"}

to get members in group and export file with

$localGroupMembers | Out-File -FilePath $reportFile -Append

And then, I want get it again with

$localGroupMembers2 = Get-Content $file

But localGroupMembers2 is not object such as localGroupMembers. So, is there a way to convert localGroupMembers2 to the same format as localGroupMembers?

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Answer 1

Rich Matheisen 47,906

Use the Export-CliXml cmdlet instead of Out-File. Then use the Import-CliXml cmdlet to recreate the object.

Trần Ngọc Nam 35 Reputation points

2023-04-25T02:16:07.4866667+00:00

Thank you for your advice. It work well. But there is way to append content into file like Out-File ?
Rich Matheisen 47,906 Reputation points

2023-04-25T02:34:51.76+00:00

No. XML is not a "flat file" of independent lines of data. XML represents a structure.

But there's nothing to prevent you from writing each object to its own file and then simply adding more files. You can import each file and add the recreated object to, say, a new array. Add additional objects to the array and export them all again.

Without knowing what you're trying to accomplish giving advice about how to do something is likely to just complicate things. Why are you saving the data to a file? What properties of the object do you need? Would using a simple CSV format be appropriate?
Trần Ngọc Nam 35 Reputation points

2023-04-26T03:51:03.37+00:00

Yeah, now I use CSV format although it is necessary to edit the data, it is the best way for now. Thank for your advice

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