Why this expression is processed from left to right?

Question

Any arithmetic operator in C has an associativity from right-to-left but why the expression in the following program is processed from left-to-right? The result of the math expression 6 - 2 + 4 is 0 according to BODMAS rule. Even if it's following the operator associativity and precedence rule the calculation should be done from right-to-left.

#include <stdio.h>

int main()
{
  int a;

  a = 6 - 2 + 4;

  printf("6 - 2 + 4 = %d", a);
  
  return 0;
}

Output:

6 - 2 + 4 = 8

Answer 1

6 - 2 + 4 is 0 according to BODMAS

What are you talking? The calculation has only add/sub, no multiply, no division, no squard.

Doesn't matter if evaluate it left-to-right or right-to-left, here comes the associative law in rule; the result is always 8.

https://en.wikipedia.org/wiki/Operator_associativity