You posted the wanted output format, but more important is the format how the date values are stored; you didn't mentioned that.
SQL nvarchar to datetime
![](data:image/svg+xml, %3Csvg xmlns='http://www.w3.org/2000/svg' height='64' class='font-weight-bold' style='font: 600 30.11764705882353px "SegoeUI", Arial' width='64'%3E%3Ccircle fill='hsl(268.8, 48%, 36%)' cx='32' cy='32' r='32' /%3E%3Ctext x='50%25' y='55%25' dominant-baseline='middle' text-anchor='middle' fill='%23FFF' %3ELB%3C/text%3E%3C/svg%3E)
Li, Bin (Health)
0
Reputation points
Hi I have a question regarding datatype nvarchar. In the table I use, a variable 'date of presentation' is nvarchar(4000), i have convert nvarchar to Britishformat using:
SELECT CONVERT(nvarchar(4000),[Date of Presentation],103) AS Britishformat
From data source
WHERE [Date of Presentation] >='01/03/2023'
Britishformat
20/08/2022
19/03/2023
13/10/2022
25/03/2023
25/01/2023
14/03/2023
But after I executed it, it seems something wrong, some records before the date have been shown below, not sure why??
Can someone help me? thank a lot.
Windows for business | Windows Client for IT Pros | User experience | Other
1 answer
Sort by: Most helpful
-
Olaf Helper 47,616 Reputation points2023-07-07T05:29:23.9066667+00:00 -
Li, Bin (Health) 0 Reputation points
2023-07-07T05:32:57.5733333+00:00 Thanks Olaf, the data type is nvarchar and stored the same way as the output.
-
Li, Bin (Health) 0 Reputation points
2023-07-07T05:34:52.2033333+00:00 It is the same format, but it is nvarchar in the data type, it looks the same.
Date of Presentation
20/08/2022
19/03/2023
13/10/2022
25/03/2023
25/01/2023
-
Li, Bin (Health) 0 Reputation points
2023-07-07T05:46:15.92+00:00 Someone designed the date as a nvarchar rather than a date format.
Sign in to comment -