Install Sub-CA in SUB-Domain

2023-08-10T11:55:59.2833333+00:00

Hi All,

we have in a Customer AD a root domain (abc.local) and some sub domains (def.abc.local, xyz.abc.local ...).

In the Headquarter there is a root CA but it is not configured. We also have no access to the domain abc.local and are only domain admins in xyz.abc.local

C:\Users\castfadmin>certutil.exe

Entry 0:

Name: 'ABC-RootCA'.
Organizational Unit: ' Organization: '
Locality: ' State: '
Country/region: ' Config: abc-cert.abc.local\ABC-RootCA'
Exchange Certificate: ' Signature Certificate: '
Description: ' Server: abc-cert.abc.local'
Authority: ABC-RootCA' Sanitized Name: ABC-RootCA'
Short Name: ABC-RootCA' Sanitized Short Name: 'ABC-RootCA Flags: '1 Web Enrollment Servers: '

CertUtil: -dump command completed successfully.

Can I build my own PKI in the sub domain xyz.abc.local (Offline root CA and SUB CA)?

Kind Regards

Windows for business | Windows Client for IT Pros | Directory services | Active Directory
Windows for business | Windows Server | User experience | Other
0 comments No comments
{count} votes

1 answer

Sort by: Most helpful
  1. Anonymous
    2023-08-15T02:37:27.4233333+00:00

    Hello René Schwaiger :: Schwaiger BUSINESS_IT,

    Thank you for posting in our Q&A forum.

    Can I build my own PKI in the sub domain xyz.abc.local (Offline root CA and SUB CA)?

    A: Do you want to set up two-tier PKI with one offline root CA (out of domain, even out of Internet) and one online enterprise sub CA(in the child domain)? If so, I think you can.

    We can make the root CA server be out of any domain and set up root AIA and root CDP on root CA server, then join the sub CA server into the child domain and set up sub AIA and sub CDP on sub CA server.

    Hope the information above is helpful. If you have any question or concern, please feel free to let us know.

    Best Regards,
    Daisy Zhou

    0 comments No comments

Your answer

Answers can be marked as Accepted Answers by the question author, which helps users to know the answer solved the author's problem.