openFileDialog.Filter

Question

In Visual Studio 2022, I encountered an issue where, in the openFileDialog.Filter property, I set the filter as follows: "file hex (.hex)|.hex". However, when I ran the program, the openFileDialog did not display .hex files. Upon inspecting the InitializeComponent() method, I found the filter set by Visual Studio 2022 to be: openFileDialog.Filter = "\"file hex (*.hex)|*.hex\""; The inclusion of backslashes and double quotes in the filter seemed to be causing the problem. After removing them, the openFileDialog worked as expected, and .hex files were displayed. Is this a bug in VS 2022?

Answer 1

Hi @Андрей Буряченко , Welcome to Microsoft Q&A,

You used poor judgment.

The correct way to write it is as follows:

openFileDialog1.Filter = "File hexadecimal (*.hex)|*.hex";
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
    string selectedFilePath = openFileDialog1.FileName;
    // Perform operations here, such as reading and processing .hex files
    MessageBox.Show("The selected file path is: " + selectedFilePath);
}

Best Regards,

Jiale

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