How to get linux OS name, version and Username in c# .net core application

Question

How to get linux OS name, version and Username in c# .net core application

BR Kiran 20

My application is running on windows as well as in linux machine.

I'm using below properties,

'System.Runtime.InteropServices.RuntimeInformation.OSDescription' to fetch OS name

'Environment.OSVersion.Version' to fetch OS version

'Environment.UserName' to fetch user name

in windows I'm getting values as expected but in linux I'm not getting the expected values.

below are the values i'm getting,

windows,

OS name : Microsoft Windows 10.0.19045

OS version: 10.0.19045

Username: TestUser

Linux,

OS name : Linux 4.18.0-372.9.1.el8.x86_64 #1 SMP Fri Apr 15 22:12:19 EDT 2022

OS version: 4.18.0.372

Username: root

expected values for linux,

OS name : RHEL

OS version: 8.8

Username: TestUser

please help me to get expected values in linux machine.

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Answer 1

Bruce (SqlWork.com) 77,686 Volunteer Moderator

typically the o/s info is in the file:

/etc/os-release

if the user is root, then the program is running under the superuser. to get the user name use the environment variable USER, or system() the utility whoami

BR Kiran 20 Reputation points

2023-10-23T09:00:47.7766667+00:00

Thanks for your answer, but I don't want to read it from the file.
Bruce (SqlWork.com) 77,686 Reputation points Volunteer Moderator

2023-10-23T15:36:48.8233333+00:00

there is no registry on linux/unix/mach, so config files are a common place to get the information.

you can use the uname() syscall to get some info:

https://man7.org/linux/man-pages/man2/uname.2.html

hint: run the uname utility to see if it lists the strings you want. I'm on a Mac so I get

Darwin XXXXX.local 23.0.0 Darwin Kernel Version 23.0.0: Fri Sep 15 14:41:34 PDT 2023; root:xnu-10002.1.13~1/RELEASE_ARM64_T8103 arm64

as these string come from the *h files during the build, there may not be custom distribution values.

also there is no standard way to get the user name programmatically. you can get the uid via the syscall getuid(), then you use this id to lookup the user name in the password file (though there can be duplicates). some distributions have added a syscall for lookup in the password file.

the unix approach of flat files for config, allows simple utilities like grep to be used to get config info.

Answer 2

Hi @BR Kiran ,

There's no good way to get linux friendly os name for now. As Bruce suggested, you could try to read the "/etc/os-release" file.

var osName = string.Empty;
var osVersion  = string.Empty;

string filePath = "/etc/os-release";

using (FileStream fileStream = new FileStream(filePath, FileMode.Open))
{
    using (StreamReader reader = new StreamReader(fileStream))
    {
        string line;

        while ((line = reader.ReadLine()) != null)
        {

            if (line.StartsWith("NAME"))
            {
                osName = line.Split('\"')[1]; //split the line string by " and get the second slice
            }

            if (line.StartsWith("VERSION_ID"))
            {
                osVersion = line.Split('\"')[1];
            }
        }
    }
}
Console.WriteLine("OS name: "+osName);
Console.WriteLine("OS version: "+osVersion);

OUTPUT

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How to get linux OS name, version and Username in c# .net core application

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