Convert percent (1 ~ 100) to a range of (0 ~ 9)

Question

Hello all,

Since the forum's bug still exists and most of the times we cannot reply to our own thread:

https://learn.microsoft.com/en-us/answers/questions/1402693/convert-percent-to-a-range-of-0-9

I've been given a method by @Jiachen Li-MSFT :

CInt(Math.Floor((percentage - 1) / 10))

But in this method 100 is expected to return 10 while it returns 9.

Actually any value more than 91 will return 9...

Answer 1

Hi @Peter Volz ,

Since 1~100 corresponds to 0~9 in your previous description, the code I provided is 1~10 corresponds to 0, 11~20 corresponds to 1, and so on.

You can remove -1 from the code so that 0~9 corresponds to 0, and 10~19 corresponds to 1.

Best Regards.

Jiachen Li

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Answer 2

oops, seems this works:

Convert.ToInt32(percentage / 10)