how to post Stream as parameter to dllImport function?

mc 3,221 Reputation points

If the c++ function need Stream? how to post it ?

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  1. Smart Smith 20 Reputation points

    If a C++ function requires a stream as an argument, you can pass it a stream object when calling the function. Here's a general example of how you can pass a stream to a C++ function:


    Copy code

    #include <iostream>

    #include <fstream>

    // Example function that takes a stream as an argument

    void processStream(std::ostream& outputStream) {

     outputStream << "This is written to the stream." << std::endl;


    int main() {

     // Example of using the function with cout (standard output)


     // Example of using the function with a file stream

     std::ofstream file("output.txt");

     if (file.is_open()) {



     } else {

     std::cerr << "Unable to open file." << std::endl;

     return 1; // Return an error code


     return 0; // Return success


    In this example, the processStream function takes a reference to std::ostream, which is a base class for output streams like std::cout (standard output) and file streams (std::ofstream). The main function demonstrates how to use processStream with both std::cout and a file stream.

    Adjust the function and the way you use it based on your specific requirements and the type of stream you want to pass to it. If you have more details about your specific use case, I can provide more tailored guidance.

    0 comments No comments

  2. Minxin Yu 8,186 Reputation points Microsoft Vendor


    MemoryStream.ToArray Method

    Writes the stream contents to a byte array, regardless of the Position property.

    Below is a test sample base on MemoryStream . Create a stream and read 20 bytes. Then copy the stream.

                // Copies the entire stream into a byte array
                byte[] buffer = memStream.ToArray();
                using (MemoryStream tempStream = new MemoryStream(buffer))


    using System;
    using System.IO;
    using System.Text;
    class MemStream
        static void Main()
            int count;
            byte[] byteArray;
            char[] charArray;
            UnicodeEncoding uniEncoding = new UnicodeEncoding();
            // Create the data to write to the stream.
            byte[] firstString = uniEncoding.GetBytes(
                "Invalid file path characters are: ");
            byte[] secondString = uniEncoding.GetBytes(
            using (MemoryStream memStream = new MemoryStream(100))
                // Write the first string to the stream.
                memStream.Write(firstString, 0, firstString.Length);
                // Write the second string to the stream, byte by byte.
                count = 0;
                while (count < secondString.Length)
                // Write the stream properties to the console.
                    "Capacity = {0}, Length = {1}, Position = {2}\n",
                // Set the position to the beginning of the stream.
                memStream.Seek(0, SeekOrigin.Begin);
                // Read the first 20 bytes from the stream.
                byteArray = new byte[memStream.Length];
                count = memStream.Read(byteArray, 0, 20);
                // Copies the entire stream into a byte array
                byte[] buffer = memStream.ToArray();
                using (MemoryStream tempStream = new MemoryStream(buffer))
                    Console.WriteLine("memstream pos is :"+memStream.Position.ToString());
                    byte[] byteArray2;
                    char[] charArray2;
                    tempStream.Seek(0, SeekOrigin.Begin);
                    byteArray2 = new byte[tempStream.Length];
                    var count2 = tempStream.Read(byteArray2, 0, 20);
                    charArray2 = new char[uniEncoding.GetCharCount(
                        byteArray2, 0, count)];
                        byteArray2, 0, count, charArray2, 0);
                    Console.WriteLine("temp stream end, below is memstream\n");
                    // Read the remaining bytes, byte by byte.
                    while (count < memStream.Length)
                        byteArray[count++] = (byte)memStream.ReadByte();
                    // Decode the byte array into a char array
                    // and write it to the console.
                    charArray = new char[uniEncoding.GetCharCount(
                        byteArray, 0, count)];
                        byteArray, 0, count, charArray, 0);

    Best regards,

    Minxin Yu

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