Parameter " Path " expects a path , not a filename .

If $file.path is $null that would point to a problem in your CSV file. Is there a column named "path" in the CSV file? Are there any empty rows in the CSV file? Does any row in the CSV have an empty value in the "path" column? Also, if you're expecting a complete path (e.g., c:\directory\name.extension) to a file to be present in the "path" column of the CSV you should probably add -PathType Leaf to the Test-Path cmdlet.

I tried to run line 10 to 16 but i get this error instead based on the snippet below. What should I do ?

PAYVINDRA SELVEN A/L TAMIL SELVEN 0

User's image

2 answers

Olaf Helper 44,501 Reputation points

2024-03-28T17:33:45.72+00:00

Parameter "Path" expects a path, not a filename.
Please sign in to rate this answer.
Rich Matheisen 46,711 Reputation points

2024-03-28T18:21:50.3433333+00:00

A complete file path is also acceptable as an argument to the -Path parameter.
Sign in to comment

Use comments to ask for clarification, additional information, or improvements to the question.
Rich Matheisen 46,711 Reputation points

2024-03-28T18:20:11.8033333+00:00

If $file.path is $null that would point to a problem in your CSV file. Is there a column named "path" in the CSV file? Are there any empty rows in the CSV file? Does any row in the CSV have an empty value in the "path" column?

Also, if you're expecting a complete path (e.g., c:\directory\name.extension) to a file to be present in the "path" column of the CSV you should probably add -PathType Leaf to the Test-Path cmdlet.
Please sign in to rate this answer.
PAYVINDRA SELVEN A/L TAMIL SELVEN 0 Reputation points

2024-03-29T00:02:53.49+00:00

Yes i have a column named path

PAYVINDRA SELVEN A/L TAMIL SELVEN 0 Reputation points

2024-03-29T00:04:23.96+00:00

I do have values in the csv file but it is not visible inside Visual Code. If i open the same csv file in desktop i can see the values

Rich Matheisen 46,711 Reputation points

2024-03-29T15:24:08.0066667+00:00

Without any data validation/reporting you're just guessing at the problem. Try something like this:

$baselineFiles = Import-CSV -Path -FilePath baselineFilePath -Delimiter "," $line = 0 foreach($file in $baselineFiles){ $line++ if ($null -eq $file.path -OR ($file.path.Trim().Length -eq 0)){ "`$file.path is null or empty on line $line" $_ continue } if(Test-Path -Path $file.path){ continue } else{ Write-Output "$($file.path) is not found" } }
Sign in to comment

Use comments to ask for clarification, additional information, or improvements to the question.

Share via

I tried to run line 10 to 16 but i get this error instead based on the snippet below. What should I do ?

2 answers

Your answer